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2 years ago

Terminating decimals are blank rational numbers never never sometimes or always

Mathematics

2 answers:

lara [203]2 years ago

3 0

They are always rational numbers

Darya [45]2 years ago

3 0

Answer:

always

Step-by-step explanation:

rational numbers are defined as A number that can be made by dividing two integers (an integer is a number with no fractional part). and that includes that

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Write the vector v in the form aiplusbj, given its magnitude left norm Bold v right norm and the angle alpha it makes with the

photoshop1234 [79]

Answer:

$6\sqrt{3}i-6j$

Step-by-step explanation:

Given:

The magnitude, v=12

The angle $\alpha$ it makes with the positive x-axis = $150^0$

Now for a vector (x,y)

$\alpha =tan^{-1}(\frac{y}{x} )$ ; and

$v=\sqrt{x^2+y^2}$

Therefore:

$150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}$

$y=-\frac{x \sqrt{3}}{3}$

Similarly:

$v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2$

$144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}$

Recall that:

$y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3} \sqrt{3}}{3}=-6$

Therefore: $(x,y)=(6\sqrt{3}, -6)$

The vector in the form ai+bj is therefore:

$6\sqrt{3}i-6j$

6 0

3 years ago

Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value u

Alenkasestr [34]

Answer:

The value is $1.75 \ and \ -1.75$

Step-by-step explanation:

From the question we are told that

The null hypothesis is $H_1 : \mu \ne 3.24$

The level of significance is $\alpha = 0.08$

From the z table the critical value of $\alpha$ considering the two tails of the normal curve( This is because this a two tailed test ) is

$z= \pm 1.75$

Hence the critical value is

$1.75 \ and \ -1.75$

5 0

2 years ago

Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am

Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = - $\frac{3}{4}$ x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.