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balandron [24]
3 years ago
13

Simplify the expression, then evaluate when x=5 and y=6. x(y+4)+3(2x+7y)

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

Simplification

x(y+4)+3(2x+7y) = xy + 10x + 21y

= x(y + 10) + 21y

On evaluation when x=5 and y=6,

The expression is equal to 206

Step-by-step explanation:

Note that x and y are unknown variables.

On expansion,

x(y+4)+3(2x+7y)

= xXy + xX4 + 3X2x + 3X7y

= xy + 4x + 6x + 21y

= xy + 10x + 21y

On factorising,

xy + 10x + 21y = x(y + 10) + 21y

Evaluation when x=5 and y = 6

We substitute the given values of x and y into the simplified expression

xy + 10x + 21y

= 5X6 + 10X5 + 21X6

= 30 + 50 + 126

= 206

Therefore, on evaluation of the given expression, when x=5 and y=6, we get 206

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Solve for x.<br> -x/3=2<br><br> x= -6<br> x= -1<br> x = 6
LenKa [72]

Answer:

x = -6

Step-by-step explanation:

Solve for x:

-x/3 = 2

Multiply both sides of -x/3 = 2 by -3:

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6 0
3 years ago
Amy gets a new kennel for her dog. A sketch of the kennel is shown here. If the roof is in the shape of a triangular prism (bott
SpyIntel [72]

Answer:

<em>Surface area of the roof of the kennel, including the bottom face is 58.96 ft^2</em>

<em></em>

Step-by-step explanation:

The image is attached below

For the triangular sides of the roof, area is

A = \frac{1}{2}bh

where b is the base = 4 ft

h is the vertical height = 2.24 ft

A =  \frac{1}{2}*4*2.24 = 4.48 ft^2

for the two faces we have 2 x 4.48 ft^2 = <em>8.96 ft^2</em>

For the rectangular sections of the roof, area is

A = lh

where l is the length of the rectangle = 5 ft

h is the height of the rectangle = 3 ft

A = 5 x 3 = 15 ft^2

For the two rectangular faces, we have 2 x 15 ft^2 = <em>30 ft^2</em>

<em></em>

For the bottom face, area is

A = lw

where l is the length of the house = 5 ft

w is the width of the house = 4 ft

A = 5 x 4 = <em>20 ft^2</em>

<em></em>

Surface area of the roof of the dog kennel is

<em>8.96 ft^2 + 30 ft^2 + 20 ft^2 = 58.96 ft^2</em>

4 0
3 years ago
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