Answer:
the top box plot should be the way to go
I would say no.
Let me know if you got it right
You need to find "two-fifths of 30." Of here means multiplication:
![\begin{aligned}\dfrac{2}{5}\cdot 30 &= \dfrac{2}{5}\cdot\dfrac{30}{1}\\[0.5em] &= \dfrac{60}{5}\\[0.5em] &= 12\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%2030%20%26%3D%20%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%5Cdfrac%7B30%7D%7B1%7D%5C%5C%5B0.5em%5D%20%26%3D%20%5Cdfrac%7B60%7D%7B5%7D%5C%5C%5B0.5em%5D%20%26%3D%2012%5Cend%7Baligned%7D)
There are 12 athletes in the club.
Answer:
78°
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relations between angles and sides of a right triangle. In particular, ...
Cos = Adjacent/Hypotenuse
cos(F) = FG/FE = 1.5/7.5 = 0.2
The inverse cosine function is used to find the angle:
∠F = arccos(0.2)
∠F ≈ 78°
Answer:
y = mx+b
Step-by-step explanation: