Ask question

Ask question

All categories

jek_recluse [69]

3 years ago

13

Ms Jones is decoring the bulletin board the media center.The billeting board is 5 ft by 9 ft rectangle.How much paper does she n

eed to cover the board

1 answer:

miv72 [106K]3 years ago

5 0

Answer:

45 ft of paper.

Step-by-step explanation:

We can find the area of a rectangle by multiplying length by width.

5 ft *9 ft = 45 ft

You might be interested in

In assessing the validity of any test of hypotheses, it is good practice to a. examine the probability model that serves as a ba

ehidna [41]

Answer:

The Correct option is - d. all of the above.

Step-by-step explanation:

To find - In assessing the validity of any test of hypotheses, it is good practice to

a. examine the probability model that serves as a basis for the test by using exploratory data analysis on the data.

b. determine exactly how the study was conducted.

c. determine what assumptions the researchers made.

d. all of the above.

Proof -

All the Given options are correct to study the validity of a hypothesis test.

So,

The Correct option is - d. all of the above.

4 0

3 years ago

Adiciona el término que hace falta para que sea un trinomio cuadrado perfecto x^2+3x+1

adell [148]

Answer:

COSAS

Step-by-step explanation:

en realidad hablo inglés XD

3 0

3 years ago

Suppose that 40% of all adults regularly consume coffee, 50% regularly consume carbonated soda, and 60% regularly consume at lea

Ad libitum [116K]

Please type the question to your problem

8 0

2 years ago

Hw 28 shades figure

ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

Part 10) $SF=0.5, x=14\ ft$

Part 11) $SF=0.5, x=3.5\ ft$

Part 12) $SF=3, x=7\ m$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

3 years ago

Find the distance between -2.5 and o.5 using subtraction

Jet001 [13]

Answer:

-3

Step-by-step explanation:

-2.5-0.5=3.0

6 0

2 years ago

Read 2 more answers