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jek_recluse [69]
3 years ago
13

Ms Jones is decoring the bulletin board the media center.The billeting board is 5 ft by 9 ft rectangle.How much paper does she n

eed to cover the board
Mathematics
1 answer:
miv72 [106K]3 years ago
5 0

Answer:

45 ft of paper.

Step-by-step explanation:

We can find the area of a rectangle by multiplying length by width.

5 ft *9 ft = 45 ft

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1/2=4p what does p equal
disa [49]
P = what times 4 equals 1/2 = 1/8
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If $3,600 is invested at a rate of 2.4% that is compounded annually, how much will it be worth after 9 years?
Alex787 [66]
Amount after 9 years = 3600( 1 + 0.024)^9  =   $4456.58
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a garden is 18 feet 3 inches long and 10 feet 8 inches wide. the amount of fencing needed to enclose the garden is Need help and
Anna [14]

Answer:

\boxed{57ft 10in}

Step-by-step explanation:

<em>Hey there!</em>

Well if the length is 18 and 3 inches we need to find the sum of both lengths,

18ft 3in + 18ft 3in = 36ft 6in

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<em>Hope this helps :)</em>

5 0
3 years ago
Find a function f such that f '(x) = 5x3 and the line 40x + y = 0 is tangent to the graph of f.
Alex17521 [72]

The function that is a  tangent to the graph of f is f(x) = (5/4)x^4+60

<h3>What is the concept of integral?</h3>

The definite integral can be interpreted as the resulting area of a region. In addition, it is a value in its result, that is, it does not depend on the variable x, which can be exchanged for any other variable without changing the value of the integral.

Knowing that :

  • 40x + y = 0 is tangent of f(x)
  • slope of the line = -40

therefore, f'(x)|x=a = -40, so only look for a we have:

5a^3 = -40\\a^3 = -8\\a = -2

if, x = -2, then y = 80 (since, 40x + y = 0), therefore, f(x) passes through (-2,80), so in the equation:

f'(x) = 5x^3\\f(x) = (5/4)x^4 + c\\80 = (5/4)(-2)^4 + c\\c = 60

Therefore,

f(x) = (5/4)x^4+60

See more about tangent at brainly.com/question/401236

#SPJ1

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2 years ago
(-5a^6 -7) -14a^6<br><br> (i’ll give brainliest)
zlopas [31]

Answer:

-19a^6 -7

are you asking to simplify??

8 0
3 years ago
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