Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:
Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:
c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:
d) The expected flight time is E(t)=122.5
Answer: 8+7
Step-by-step explanation: 3+5+7 is equivalent to 8+7 because if you add the both of them you’ll get the same exact answer which is 15
The quadratic formula is the result of completing the square for ax^2+bx+c=0 when a,b, and c are unknown values. This result is:
x=(-b±√(b^2-4ac))/(2a), we have x^2-x-2=0 so
x=(1±√(1+8))/2
x=(1±√9)/2
x=(1±3)/2
x=-1 and 2
If you're looking for where they intersect, then I think the answer is c
Hello!
Let's write some important information contained in the exercise:
• hotdogs: $2.59 (,x,)
,
• hamburgers: $5.29 (,y,)
He needs 11 packages. Let's write it:
• x + y = 11
He spent a total of $39.29. We can write it as:
• 2.59x + 5.29y = 39.29
Now, let's solve these two equations as a linear system:
First, let's isolate x in equation A:
Now, we will replace where's x by 11-y in equation B:
As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.
