Suppose a die is rolled twice and let P(A) = 1/2 P(B) = 1/3 find the requested probability
1 answer:
Answer:
Step-by-step explanation:
P(AUB)=P(A)+P(B)+P(A∧B),P(A∧B)=0 as both the events are independent.
P(AUB)=1/2+1/3=(3+2)/6=5/6
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