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Mashcka [7]
3 years ago
14

What is the value of x in 16 to the 2nd power = x

Mathematics
2 answers:
Blababa [14]3 years ago
5 0
The value of x in the equation 16 to the 2nd power=x; is x=256
Zepler [3.9K]3 years ago
4 0
16^2 is 16•16 so x would equal 256
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Find the values of x and y in the parallelogram when AB=x^2-18, CD=7x, mD=(5y+31), mB=96
Fynjy0 [20]

Greetings, I Am BrotherEye

Answer:

AP = CP, BP = DP; sample answer: If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram, so if AP = CP and BP = DP, then the string forms a parallelogram. ALGEBRA Find x and y so that the quadrilateral is a parallelogram. BP = DP, then the string forms a parallelogram.

Step-by-step explanation:

Answer: B

8 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
Please help me. I'm lost.
amm1812
Yes cause he can decrease the perimeter in any way and it would change the area and idk the other 2 in the front
6 0
3 years ago
What is the absolute value of 2 and -2?
xeze [42]

If you mean |2-2| then the absolute value is 0

If you are talking about |2| |-2| then the absolute values are 2 and 2

6 0
3 years ago
Complete the solution the equation. Find the value of y when x equals 15 .
LekaFEV [45]
-15+15 - 9y =39+15
-9y=54
y= -6
7 0
2 years ago
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