Help please with this question?

Mathematics

2 answers:

GaryK [48]2 years ago

6 0

This is the same problem you answer is 12/13. One more brainliest if this is truly correct good luck.

Aliun [14]2 years ago

4 0

36/39 or 12/13 is th answer to that

You might be interested in

2: Write an equation for the line in slope-intercept form.

Finger [1]

Answer:

Step-by-step explanation: The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept.

7 0

2 years ago

Read 2 more answers

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t

Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

<h3>What is sequence ?</h3>

Sequence is collection of numbers with some pattern .

Given sequence

$a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20$

We can see that

$\frac{a_1}{a_2}=\frac{-10}{5}=-2\\$

and

$\frac{a_2}{a_3}=\frac{20}{-10}=-2\\$

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now $n^{th}$ term of this Geometric progression can be written as

$T_{n}= 5\times(-2)^{n-1}$

So summation of 15 terms can be written as

$\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0

2 years ago

Juan cuts a piece of paper in half. he then cuts each half into thirds and each of those pieces into eights. finally, he cuts ea

Nookie1986 [14]

Answer:

D: 768

Step-by-step explanation:

First, he divides a piece of paper in half.

$1 \div \frac{1}{2} = 2$