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SVETLANKA909090 [29]
3 years ago
12

Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds using percentages how much better was her second lap

when comapared to her first lap
Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

Her second lap was <u>8%</u> better when compared to her first lap.

Step-by-step explanation:

Given:

Emily ran her first lap in 75 seconds she ran her second lap in 69 seconds.

Now, to find how much better was her second lap when compared to her first lap.

Emily ran her first lap in 75 seconds.

Emily ran her second lap in 69 seconds.

So, we get the difference in seconds:

75-69=6\ seconds.

<u><em>Thus, in her second lap she was 6 seconds better than first.</em></u>

Now, to get the percentage of her first lap better than second:

\frac{6}{75}\times 100

=0.08\times 100

=8\%.

Therefore, her second lap was 8% better when compared to her first lap.

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Answer:

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Step-by-step explanation:

The height of the object can be determined by:

\frac{object distance from pinhole}{image distance from pinhole} = \frac{object height}{image height}

From the given question;

object distance from pinhole = 3.6 m = 360 cm

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So that;

\frac{360}{4.2} = \frac{object height}{0.8}

⇒ object height = \frac{360*0.8}{4.2}

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object height = 68.6 cm

Thus, the height of the object is 68.6 cm.

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