Answer: 2/15
Believe me I put the same thing and I got it correct.
Answer:
2.46
3.63
195,929.85
236,551.79
35.39
34.31
B
Step-by-step explanation:
Explaining it is kind of akward, but I can explain if you want.
Not too sure about the last one, but the rest I feel good about
9514 1404 393
Answer:
(d) 28
Step-by-step explanation:
When you are asked to evaluate g(n) for some value of n, put that value where n is and do the arithmetic.
g(n) = 3n -2
g(10) = 3·10 -2
= 30 -2 = 28
The amount of dollars that Mr. Levant would exchange for 100 pesos on his return is <u>$9</u>.
<h3>What is an exchange rate?</h3>
An exchange rate is a rate that is used to convert one nation's currency to another.
The exchange rate is based on the purchasing power of each nation's currency.
<h3>Data and Calculations:</h3>
Dollars before traveling to Mexico = $270
Value of Mexican pesos received for $270 = 3,000 pesos
Exchange rate = $1 = 11.11 pesos (3,000/$270)
Amount of pesos left after the trip = 100 pesos
Value of 100 pesos in dollars = <u>$9</u> (100/$11.11)
Thus, the amount of dollars that Mr. Levant would exchange for 100 pesos on his return is <u>$9</u>.
Learn more about exchange rates at brainly.com/question/2202418
#SPJ1
Answer:
a) Q1= 144.10
Median = 150
Q3=155.90
b) The 99 percentile would be:
And represent a value who accumulate 99% of the values below
Step-by-step explanation:
Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:
Where and
Part a
Lets begin with the first quartile:
(a)
(b)
We can find the quantile in the normal standard distribution and we got z=-0.674.
And we can apply the z score formula and we got:
And if we solve for a we got
The median for this case is the mean
For the third quartile we find the quantile who accumulate 0.75 of the area below and we got z=0.674 and we got:
Part b
We can find the quantile in the normal standard distribution who accumulate 0.99 of the area below and we got z=2.33.
And we can apply the z score formula and we got:
And if we solve for a we got
And represent a value who accumulate 99% of the values below