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SVEN [57.7K]
3 years ago
10

PLEASE HELP ASAP!!!!

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

1 to 5

211 to 1500

11 to 300

Step-by-step explanation:

1.8 to 9 = 18/90 = 1(18)/5(18) = 1/5 = 1 to 5

2.11 to 15 = 211/1500 = 211 to 1500

3.30 to 90 = 330/9000 = 110/3000 = 11/300 = 11 to 300

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9th

Maths

Surface Areas and Volumes

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A cylindrical container wit...

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

4 0
3 years ago
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