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Anton [14]
3 years ago
11

HELP PLEASE!!! I need help with this question!

Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

\large\boxed{PS=10\sqrt5}

Step-by-step explanation:

ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:

\dfrac{QR}{RP}=\dfrac{RP}{RS}

We have:

QR=5,\ RS=20

Substitute:

\dfrac{5}{RP}=\dfrc{RP}{20}                <em>cross multiply</em>

RP^2=(5)(20)\\\\RP^2=100\to RP=\sqrt{100}\\\\RP=10

Use the Pythagorean theorem:

PS^2=PR^2+RS^2

Substitute:

PS^2=10^2+20^2\\\\PS^2=100+400\\\\PS^2=500\to PS=\sqrt{500}\\\\PS=\sqrt{100\cdot5}\\\\PS=\sqrt{100}\cdot\sqrt5\\\\PS=10\sqrt5

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