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2 years ago

HELP PLEASE!!! I need help with this question!

Mathematics

1 answer:

AlexFokin [52]2 years ago

6 0

Answer:

$\large\boxed{PS=10\sqrt5}$

Step-by-step explanation:

ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:

$\dfrac{QR}{RP}=\dfrac{RP}{RS}$

We have:

$QR=5,\ RS=20$

Substitute:

$\dfrac{5}{RP}=\dfrc{RP}{20}$ cross multiply

$RP^2=(5)(20)\\\\RP^2=100\to RP=\sqrt{100}\\\\RP=10$

Use the Pythagorean theorem:

$PS^2=PR^2+RS^2$

Substitute:

$PS^2=10^2+20^2\\\\PS^2=100+400\\\\PS^2=500\to PS=\sqrt{500}\\\\PS=\sqrt{100\cdot5}\\\\PS=\sqrt{100}\cdot\sqrt5\\\\PS=10\sqrt5$

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A l-meter steel rod is bent into a rectangle so that its length exceeds quadruple its width

Dmitry_Shevchenko [17]

Answer:

The dimensions of the newly formed rectangle is length is 41 cm and width is 9 cm.

Step-by-step explanation:

Given,

A 1 meter steel rod is bent into a rectangle.

That means the perimeter of the rectangle is 1 meter.

So, Perimeter = $1\ m=100\ cm$

Let the width of the rectangle be 'x'.

Now According to question, length exceeds quadruple its width by 5 cm.

Hence framing the above sentence in equation form, we get;

$Length=4x+5$

Now we use the formula of perimeter of rectangle,

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On substituting the values, we get;

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$Length=4x+5=4\times9+5=36+5=41\ cm$

Thus, Width=9 cm Length=41 cm

Hence the dimensions of the newly formed rectangle is length is 41 cm and width is 9 cm.

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2 years ago

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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