Answer:
P = -12xy - 56y - 42x + 8
Step-by-step explanation:
P = 2L + 2W
P = 2(4 - 7(3x + 4y)) + 2(3x(-2y))
P = 8 - 14(3x + 4y) + 6x(-2y)
P = 8 - 42x - 56y - 12xy
P = -12xy - 56y - 42x + 8
Answer: Infinitely many
Step-by-step explanation: 2(x-3)=10x-6-8x
2x-6=10x-6-8x
2x-6=2x-6
Answer:
Step-by-step explanation:
GIVEN: two two-letter passwords can be formed from the letters A, B, C, D, E, F, G and H.
TO FIND: How many different two two-letter passwords can be formed if no repetition of letters is allowed.
SOLUTION:
Total number of different letters 
for two two-letter passwords 
different are required.
Number of ways of selecting different letters from 
letters
Hence there are different two-letter passwords can be formed using letters.
<u>Solution-</u>
Zachary purchased a computer for 1800 on a payment plan. (Initial Money)
3 months after he bought the computer, his balance was 1350. (Money after 3 months)
Total money paid in 3 months = 1800-1350 = 450
Money paid per month = 450/3 = 150
5 months after he bought the computer, his balance was 1050.
Total spent = 1800-1050 = 750 = (5× 150)
So the equation that models the balance b after m months,
b = 1800 - m(150)
∴ Here, the slope signifies the constant monthly deduction of $150.
Answer:
A, the graph is shown
Step-by-step explanation:
