The range of a function is the set of output values of the function
The range of the function is: {15, 6, 4, 0}
<h3>How to determine the range</h3>
The function is defined as:
(x,y) = {(0, 15), (4, 6), (6, 4), (8, 0)}
The range is the y-values.
So, we have:
y = {15, 6, 4, 0}
Hence, the range of the function is: {15, 6, 4, 0}
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Well I solved it and This is what i got
Answer:
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate
10%. The second car depreciates at an annual rate of 15%. What is the approximate difference in the ages of the two
cars?
Step-by-step explanation:
the answer is in the question
Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
1 out of every 3 races could be won by Rachelle
Step-by-step explanation: