All categories

3 years ago

(a)b - 0.5b when a = 1 and b = 5

Mathematics

2 answers:

Allisa [31]3 years ago

7 0

Answer:

(1)5 - 0.5(5) = 5 - 2.5 =======2.5

Step-by-step explanation:

MAXImum [283]3 years ago

3 0

Answer:

2.5

Step-by-step explanation:

$(a)b-0.5b$

Substitute 'a' and 'b' for the appropriate values:

$(1)5-0.5(5)$

Solve:

$(1)5-0.5(5)\\\\5-2.5\\\\\boxed{2.5}$

Hope this helps.

You might be interested in

How do u write 4408730 in expanded form?

STALIN [3.7K]

Do you need the expanded notation form, or expanded factor form?

5 0

3 years ago

What is the circumference of a circle whose radius is 20 feet? Leave answer in terms of π.

lesantik [10]

Answer:

What is the circumference of a circle whose radius is 20 feet? Leave answer in terms of π.

A) 10π feet

B) 20π feet

<u> C) 40π feet </u>

D) 100π feet

Step-by-step explanation:

circumference = 2πr

circumference=2×π×20

circumference=40π

5 0

3 years ago

Read 2 more answers

1. Pedro is a good student.<br> a.<br> b.

ICE Princess25 [194]

Answer:

your answer is (A)

Step-by-step explanation:

in the affirmative

plz mark me as brainlist

5 0

3 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

Read 2 more answers

Pls help I’ll add extra points

Alenkasestr [34]

Answer:

1. Immune

Step-by-step explanation:

5 0

2 years ago

(a)b - 0.5b when a = 1 and b = 5​

(a)b - 0.5b when a = 1 and b = 5