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r-ruslan [8.4K]
3 years ago
15

What is the algebraic expression for 11 more than twice a number x

Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

11+2x

Step-by-step explanation:

QveST [7]3 years ago
3 0

Answer:

2x + 11

Step-by-step explanation:

"twice a number x": Multiply the variable x with 2 ⇒ 2x

"11 more than...": Add 11 ⇒ + 11

Combine the two terms:

2x + 11 is your answer.

~

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Explain hovevou could estimate 22% of 78 to check if your answer is reasonable.
fomenos

Answer:

78 rounds to 80, so find 10% of 80 and double it. 10% of 80 is 8. So, 20% of 80 is 16. Then, 22% of 78 is a little more than 16.

78 rounds to 80, and 22% is a little less than 25%. 25% (or one-fourth) of 80 is 20. So, 22% of 78 is a little less than 20.

Step-by-step explanation:

8 0
3 years ago
7
ella [17]

Given:

Two similar rectangles.

To find:

The area of the larger rectangle.

Solution:

Let x be the other side of the larger rectangle.

Corresponding sides of similar figures are always congruent.

\dfrac{x}{1}=\dfrac{4}{2}

x=2

The other side of larger rectangle is 2 cm.

We know that, area of rectangle is

Area=Length\times Width

So, area of the larger rectangle is

Area=4\times 2

Area=8

Therefore, the area of the larger rectangle is 8 sq. cm.

6 0
3 years ago
Solve the absolute value equation 3x+2 =2 plz
Umnica [9.8K]
It is x=0 and x=-4/3
8 0
3 years ago
Read 2 more answers
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
Divide the following problem by hand (long division). Report your answer as a decimal (not remainder). (Show your work).
Agata [3.3K]

Answer:

122.88

Step-by-step explanation:

<u>3072</u>

25

122.88 sorry I forgot how to show all the work I love my calculator but hopefully the answer you need will help.

4 0
3 years ago
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