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grin007 [14]
3 years ago
5

How to solve these numbers I forgot

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0

40 because 3+6+12 = 21 and 8+11+21 =40

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How do i solve 6x=5x+7 by using solving systems by elimination?
klio [65]
I just learned about it. Simple!

6x=5x+7
Subtract 5x from both sides.
-5x -5x
You end up with
1x=7   or  x=7



7 0
3 years ago
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Brainly.com
Slav-nsk [51]
The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range.  So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.  
|18.62-18.25|>.36
.37>.36
18.62 is not in range.





7 0
3 years ago
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Help help help help help
shtirl [24]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
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What Number between 77 177can be divided evenly by 8
sergiy2304 [10]
176 divided by 8 = 22
So 176 can be evenly divided by 8
4 0
3 years ago
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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
3 years ago
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