997/1000, or just round it to 1. <em>If I helped click thanks please (:</em>
If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
Answer:
y=3/2(x) -1, or y = 1.5x - 1
Step-by-step explanation:
To write the equation in slope-intercept form, you have to determine the y-intercept for the line. Since you have the slope and at least one ordered pair, you can find this by substituting the points and slope into this formula:
y=mx+b.
For this particular line, you would write:
-8 = 3/2(-6)+b
-8 = -18/2 + b
-8 = -9 + b
add 9 to both sides to isolate the b
-1 = b.
Now that you have the answer for b (-1), you can write the equation as:
y=3/2(x) -1
