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QveST [7]
3 years ago
10

A pink-and-green spinner landed on pink 14 times and on green 56 times. Based on experimental probability, how many of the next

65 spins would you expect to land on pink?
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0
<h3>Answer:  13</h3>

=========================================================

Explanation:

Based on the results so far, the experimental or empirical probability of landing on pink is 14/(14+56) = 14/70 = 1/5.

You simply divide the number of pink (14) over the number total (14+56=70) to arrive at that fraction. After reducing, we get 1/5 meaning that 1 out of every 5 spins we arrived on a pink space.

If this pattern holds up, then we expect (1/5)*65 = 13 additional occurrences of pink on the next 65 spins.

Note how 13/65 = 1/5.

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Find the value of x in the triangle shown below 8 2
Anit [1.1K]

Answer:

8.25

Step-by-step explanation:

(8x 8) + (2x2) = x ^2

64 + 4 = x2

x = √68

x = 8.25

3 0
3 years ago
What means the same as 6 × 5? <br> A.6^5 <br> B.5 + 5 + 5 + 5 + 5 <br> C.6 + 6 + 6 + 6 + 6
skelet666 [1.2K]

Here is your answer:

In order to find your answer we will have to solve each option separately to see which one equals 6 × 5.

  • 6^5 = 6\times6\times6\times6\times 6 <---- Not the answer
  • 5 + 5 + 5 + 5 + 5 = 25 <----- Not the answer
  • 6 + 6 + 6 + 6 + 6 = 35 <---- Your answer

Therefore your answer is option C "6 + 6 + 6 + 6 + 6 ."

Hope this helps!

8 0
3 years ago
Read 2 more answers
Samuel pays $20 for a shirt that is on sale. If he saved $5, what is the percent of the discount?
Reptile [31]
The answer to your question is A; .25% because if you take 20 and multiply it by .25, you'll get 5 for an answer. Hope this helped!

5 0
3 years ago
Find the exact value, without a
alexira [117]

Answer:

-2 -\sqrt{3}

Step-by-step explanation:

<u><em>First consider numerator</em></u>

sin \frac{\frac{7\pi}{6}}{2} = sin \frac{7\pi}{12}= sin (\frac{\pi}{4} + \frac{\pi}{3})

Using the formula : sin (A + B) = sin A cos B + cos A sin B

sin  \frac{\pi}{4} = \frac{\sqrt{2} }{2}, \ cos  \frac{\pi}{4} = \frac{\sqrt{2} }{2}\\\\sin \frac{\pi}{3} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{3} = \frac{1}{2}

sin(\frac{\pi}{4} + \frac{\pi}{3}) = sin \frac{\pi}{4}  \cdot cos  \frac{\pi}{3} + cos \frac{\pi}{4} \cdot sin \frac{\pi}{3}

                =\frac{\sqrt{2} }{2} \cdot \frac{1}{2} + \frac{\sqrt{2} }{2} \cdot \frac{\sqrt{3} }{2} \\\\= \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}\\\\=\frac{\sqrt{2} +\sqrt{6} }{4}

<u><em>Second consider denominator</em></u>

cos \frac{\frac{7\pi}{6}}{2} = cos \frac{7\pi}{12}= cos (\frac{\pi}{4} + \frac{\pi}{3})

Using the formula : cos (A + B) = cos A cos B - sin A sin B

sin  \frac{\pi}{4} = \frac{\sqrt{2} }{2}, \ cos  \frac{\pi}{4} = \frac{\sqrt{2} }{2}\\\\sin \frac{\pi}{3} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{3} = \frac{1}{2}

cos(\frac{\pi}{4} + \frac{\pi}{3}) = cos \frac{\pi}{4}  \cdot cos  \frac{\pi}{3} -sin \frac{\pi}{4} \cdot sin \frac{\pi}{3}

=\frac{\sqrt{2} }{2} \cdot \frac{1}{2} - \frac{\sqrt{2} }{2} \cdot \frac{\sqrt{3} }{2}\\\\=\frac{\sqrt{2}}{4} -  \frac{\sqrt{6}}{4}\\\\= \frac{\sqrt{2} -\sqrt{6} }{4}

Therefore,

           tan \frac{7\pi}{12} = \frac{sin \frac{7\pi}{12}}{cos\frac{7\pi}{12}}

                     = \frac{\frac{\sqrt{2} +\sqrt{6} }{4}} {\frac{\sqrt{2} -\sqrt{6} }{4} }\\\\=\frac{\sqrt{2} +\sqrt{6} }{4} \times \frac{4 }{\sqrt{2} -\sqrt{6}}\\\\=\frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} -\sqrt{6}}

Either we can stop here or Rationalize the denominator:

\frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} -\sqrt{6}} \times \frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} +\sqrt{6}} = \frac{(\sqrt{2} +\sqrt{6})^{2} }{(\sqrt{2})^2 -(\sqrt{6})^2} = \frac{2 + 6 +2\sqrt{12} }{2-6} = \frac{8+2\sqrt{12} }{-4} = \frac{8+ 4\sqrt{3} }{-4} = -2-\sqrt{3}

3 0
3 years ago
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kobusy [5.1K]

both variables are x

pretend there is an imaginary 1 in front of the x for x squared

3 x 1 = 3

x^2 x X = x^3

this is because when multiplying numbers with the same variable like this problem for instance then you add the squared (2) with the x ( imaginary 1)

so 3x^3 is the answer



5 0
4 years ago
Read 2 more answers
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