3^3*5^2*13 is the prime factorization of 8775
Given:
Initial point = (–5, 3)
Terminal point = (1, –6)
To find:
The set of parametric equations over the interval 0 ≤ t ≤ 1.
Solution:
The interval is 0 ≤ t ≤ 1, initial point is (–5, 3) and terminal point is (1, –6). It means,


Put t=1 in each parametric equation.
In option A,

In option B,

In option D,

Therefore, options A, B and D are incorrect.
In option C,


Put t=0 in x(t) and y(t).


Since, only in option C
, therefore, the correct option is C.
Answer:
Odd is the answer.
Step-by-step explanation:
An even number can be written in the form 2x, where x is an integer.
An odd number can be written in the form 2x + 1, where x is an integer.
So two odd numbers can be represented by 2a +1 and 2b +1, the product would be:
(2a + 1)(2b +1) = 4ab + 2a + 2b + 1 = which can be written as 2(2ab + a +b) + 1, but 2ab +a + b represents some integer, so 2ab + a + b = x.
So (2a + 1)(2b + 1) = 2(2ab + a + b ) + 1 = 2x +1 which is odd.
Answer:
The notation from analyzing the Karnaugh map is:
F(X,Y,Z) = X'Y'Z + X'Z'Y + Y'Z'X
With logical functions would be:
F(X,Y,Z) = (NOT(X AND Y) AND Z) OR ((NOT Z) AND (X XOR Y))
Step-by-step explanation:
You can reduce the logical function with a Karnaugh map, like the attached, notice the gray coding notation, to assure only one variable change at each cell.