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Delvig [45]
3 years ago
7

Suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7,1). write an equat

ion of the parabola in vertex from.
Y = -4(x-5)^2+9
Y = -7(x+9)^2 - 5
Y = -0.06(x-5)^2 + 9
Y = -2(x+5)^2 + 9

Help please...
Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

We are given

a parabola has an axis of symmetry at x = -5, a maximum height of 9

so, we get

vertex =(-5,9)

vertex=(h,k)=(-5,9)

so, h=-5 and k=9

we can use vertex form of parabola

y=a(x-h)^2+k

we can plug these value

y=a(x+5)^2+9

now, it passes through the point (-7,1)

we can use it and then we can solve for a

1=a(-7+5)^2+9

4a+9=1

4a=-8

a=-2

So, we will get equation of parabola as

y=-2(x+5)^2+9..............Answer


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Answer:

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Step-by-step explanation:

The inverse of f(x)=2^x is g(x)=\log_2(x).

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<h2>Explanations:</h2>

Given the following expression show below;

\frac{11y-110}{50-5y}

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