Answer:
$31.61
Explanation:
In order to determine the amount of interest charged you must first calculate the average daily balance:
average daily balance = [($2,030 x 9) + ($1,450 x 22)] / 31 = $1,618.39
Now we must calculate the daily interest rate:
daily interest rate = 23% / 365 = 0.063%
Finally we multiply the average daily balance times the daily interest rate times the number of days in the billing period:
interest charged = $1,618.39 x 0.063% x 31 days = $31.61
Answer:
a. $17,978
b. $300,000
Explanation:
Conditions
- The cotton country of lancaster, california has owned his home for ten years
- purchased it for $178,000, cotton bought a $160,000 homeowner's insurance policy
- the replacement cost of the home is now $300,000
a. hence,
the proportion of the house insured =
%
![= \frac{160000}{178000}\times 100](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B160000%7D%7B178000%7D%5Ctimes%20100)
= 89.89%
Percentage amount covered by the policy
= proportion of the house insured = 89.89%
Amount covered by the policy in dollars
= $20,000 × 89.89%
= $17,978
b
Amount of insurance on the home that cotton should now carry to be fully reimbursed for a fire loss = current value of the home
= $ 300,000
Answer: higher than
Explanation: The stockholders of companies in the infant industry gain when they are protected from world competition
-Consumes in that country will therefore pay a price higher than the world price.
The correct answer for the for loop is:
for (int i=1; i<200; i++){
if ((i%2)==0 && (i%3)==0){
cout << i << " ";
}
}
Python offers three options for running the loops. For iterating repeatedly through a sequence, use a for loop (that is either a list, a tuple, a dictionary, a set, or a string). This functions more like an iterator method seen in other object-oriented programming languages and is less like the for keyword found in other programming languages. The for loop allows us to run a series of instructions once for each element of a list, tuple, set, etc. There is no need to set an indexing variable before using the for loop.
Write a for loop that prints, in ascending order, all the positive integers less than 200 that are divisible by both 2 and 3, separated by spaces.
Learn more about loops here:
brainly.com/question/25955539
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