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Tanya [424]
3 years ago
10

What’s the square root of one million?

Mathematics
2 answers:
Nitella [24]3 years ago
5 0

Answer:

1000

Step-by-step explanation:

klio [65]3 years ago
4 0

Answer:

1000

Step-by-step explanation:

If you do 1000 x 1000 you will get 1 million

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5/12 expressed as a decimal fraction is? (Round to the nearest thousandths)
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Answer:

5/12 = 0.416666667 if you round up to the nearest thousandths it would be 0.417

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A small company manufacturers a certain item and sells it online. The company has business model where the cost C, in dollars, t
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Answer:

Step-by-step explanation:

We know that the break even point is the point where the cost and the revenue equations intersect.  So the break even point in this situation is:

C= R

<=> 20/3x+50 = 10x (with x > 0 and x is a whole number)

<=> 10x^{2} -50x -20 = 0

<=> x ≈ 5

If the company sells more than 5 items, it will have benefit

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solve the equation 5x=25
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x=5

Step-by-step explanation:

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3 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

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3 years ago
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