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melomori [17]
3 years ago
5

Juan has 12 muffins. He puts 1/4 of the muffins in a bag. How many muffins does Juan put in the bag?

Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0
●●●\●●●\●●●\●●● muffins


●●● goes on the bag

3 muffins go in the bag.
Kitty [74]3 years ago
3 0
12 divided my four is 3. So three is your answer.
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Law of sines: How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?
butalik [34]
According to the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

Using the given values, we can find the angle B and find the number of possible triangles that can be formed.

\frac{2}{sin(75)}= \frac{3}{sin(B)} \\  \\ 
sin(B)=3* \frac{sin75}{2}  \\  \\ 
sin(B)=1.45 \\  \\ 
B=sin^{-1} (1.45)

The range of sin is from -1 to 1. The above expression does not yield any possible value of B, as sin of no angle can be equal to 1.45.

Therefore, we can conclude that no triangle exists with the given conditions.
5 0
3 years ago
The ratio of cars to trucks is 8 cars to 36 trucks. If there are 9 trucks, how many cars are there?
solniwko [45]
Set up the proportion with the numbers on top equalling the cars and the numbers on the bottom representing the trucks.
\frac{8}{36} = \frac{c}{9}
c equals the number of unknown cars.
To solve the proportion, cross multiply (multiply 8 by 9 and 36 by c) and solve for c.
72 = 36c
Divide 36 from both sides to get the answer.
c = 2
If there are 9 trucks, there are 2 cars.
You can check this by dividing 2 by 9, and dividing 8 by 36. Since they both equal the same number, this answer is correct.

Hope this helps =)

8 0
3 years ago
Read 2 more answers
Question:
prohojiy [21]
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').) 
Write this in cases: 
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant. 
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0. 
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b. 
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function. 
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x). 
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.) 
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have. 
I hope this helps!
4 0
3 years ago
F + 25 = 50<br><br> f = <br><br> please help
Xelga [282]

Answer:

25 because 50 minus 25 is 25

5 0
2 years ago
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What are the solutions to the system of equations? y=x2−5x−6 y=2x−6
Leya [2.2K]

Answer:

I graphed both equations to find the solutions.

Step-by-step explanation:

When x is 0, y is -6. When x is 7, y is 8.

x = 0 and 7

4 0
3 years ago
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