<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Here, we just use the following x values and put them into the equation.
y = - 0.05x + 16
y = -0.5(0) + 16
y = 16
y = - 0.05x + 16
y = -0.5(160) + 16
y = -80 + 16
y = -64
y = - 0.05x + 16
y = -0.5(320) + 16
y = - 160 + 16
y = -144
Now, to set up the table, you could list the x values and the y values.
x values :- 0,160, 320
y values:- 16, -64, -144
The area shaded in green is 864 cm²
<h3>Similar figures</h3>
Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,
AB / PQ = CD / RS
30 / 10 = 24 / RS
30RS = 240
RS = 240 / 30
RS = 8 cm
let find the height of trapezium PQRS.
AB / PQ = 36 / h
30 / 10 = 36 / h
30h = 360
h = 360 / 30
h = 12 cm
Therefore,
area of the green portion = area of ABCD - area of PQRS
<h3>Area of a trapezium</h3>
Therefore,
area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²
area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²
Area of the green portion = 972 - 108 = 864 cm²
learn more on trapezium here: brainly.com/question/11961445
Answer:
<h3>
X = 2 , X = -3</h3>
Option C is the correct option.
Step-by-step explanation:
Discriminant = 
Given d = 15
When discriminant D > 0 --> roots are real and distinct. ( unequal )
So , 
option has real and distinct roots.
Hope this helps..
Best regards!!
