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3 years ago

How to write in a single power?

Mathematics

1 answer:

nekit [7.7K]3 years ago

7 0

Write what??
<em>n single power??</em>

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Solve the following quadratic function<br> by utilizing the square root method.<br> y = 16 – x2

xxMikexx [17]

Answer:

The solutions are x = -4 and x = 4.

Step-by-step explanation:

Solving a quadratic equation:

We have to find x for which $y = 0$ .

In this question:

$y = 16 - x^2$

$16 - x^2 = 0$

$x^2 = 16$

$x = \pm \sqrt{16}$

$x = \pm 4$

The solutions are x = -4 and x = 4.

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Answer:

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Step-by-step explanation:

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3 years ago

What is 9 1/10 - 4 3/4

Nady [450]

Answer:

$\frac{87}{20}$

Step-by-step explanation:

First we need to change the mixed numbers into improper fractions.

9 x 10 = 90 + 1 = 91/10

4 x 4 = 16 + 3 = 19/4

Now we need to get them into simplest terms. There is a few ways to do this, but I know that 10 x 2 = 20 and 4 x 5 = 20 so I will use 20.

$\frac{91}{10} = \frac{91 x 2}{10 x 2} = \frac{182}{20}$

$\frac{19}{4} = \frac{19 x 5}{4 x 5} = \frac{95}{20}$

Now we can subtract:

$\frac{182}{20} - \frac{95}{20} = \frac{87}{20}$

And that leaves us with our answer :D

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3 years ago

For what values of θ are the magnitudes of the scalar product and the vector product equal?

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Answer:

For vectors given by their components: A = (Ax, Ay, Az) and B = (Bx, By, Bz), the scalar product is given by A · B = AxBx + AyBy + AzBz Note that if θ = 90°, then cos (θ) = 0 and therefore we can state that: Two vectors, with magnitudes not equal to zero, are perpendicular if and only if their scalar product is equal to zero.

Step-by-step explanation:

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Step-by-step explanation:

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