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3 years ago

Find the ordered-pair solution of y=3x-2

Mathematics

1 answer:

almond37 [142]3 years ago

5 0

Answer:

(0, 2

Step-by-)step explanation:

x = 0, y = -2

(0, 2)

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One fourth of the 120 students took wood shop. How many students did not take wood shop?

yawa3891 [41]

Answer:

90 students.

Step-by-step explanation:

Given 1/4 of the 120 students took woodshop, just take the 3/4 that didn't take it:

$\frac{3}{4}(120)$

Find common factors between 4 and 120 to simplify, so 4.

$\frac{3}{1} (30)$

Now multiple across to get 90.

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3 years ago

Trent went skiing with his family. His mom and dad made him put on many different layers of clothing so that he would be warm wh

mafiozo [28]

I think the answer is A. conductor

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3 years ago

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Expand and simplify (6x-2)^2<br>

IgorLugansk [536]

Answer:

$\sf 36x^2 -24x +4$

solving step wise:

$\sf (6x-2)^2$

$\sf (6x-2)(6x-2)$

$\sf 36x^2 -12x -12x +4$

$\sf 36x^2 -24x +4$

$\sf (6x-2)^2$

$\sf (6x)^2 +2*6x*-2+(-2)^2$

$36x^2 -24x +4$

4 0

3 years ago

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What is the perimeter of a square if the is a length of 4x and a width of 36-5x?

yulyashka [42]

4x=36－5x
x=4

The perimeter of the square=4x4×4
=64

7 0

3 years ago

Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and

torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

$P(X=x) = C(n,x)p^{x} (1-p)^{n-x}$

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

$C(n,x) = \frac{n!}{x!(n-x)!}$

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

$p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102$

b) At least 3 customers make a purchase. x ≥ 3

$P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557$

c) At most 2 customers make a purchase. x ≤ 2

$P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443$

d)At least 1 customer makes a purchase. x ≥ 1

$P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824$

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

6 0

3 years ago