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4 years ago

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The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present age

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1 answer:

yuradex [85]4 years ago

4 0

Answer:

Hari is 20; Harry is 28

Step-by-step explanation:

The ratio in 4 years is equivalent to the ratio 6:8, which has each of the original ratio unit numbers increased by 1. That means each of those ratio units stands for 4 years, and the present ages are ...

Hari: 5·4 = 20

Harry: 7·4 = 28

_____

<em>Conventional method of solution</em>

If you like, you can write equations for the ages of Hari (x) and Harry (y):

x/y = 5/7

(x+4)/(y+4) = 3/4

These can be solved a variety of ways. For some methods, it may be useful to write them in standard form:

7x -5y = 0
4x -3y = -4

These have solution (x, y) = (20, 28).

You might be interested in

What is the answers of 6b and 6c?

Dimas [21]

Hello,

6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.

So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop

The answer is 37%.

(ii) For this question, we basically have the same process as the previous question except for the second year.

From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop

The answer is 12%.

6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.

The initial value of the car is 27,000, and after 5 years the value is 8,000.
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.

The answer is 70%.

Hope this helps!

7 0

4 years ago

You make an initial investment of $500. Fill in the table below to show how much money you would have after 3 years if your acco

Aleksandr [31]

After three years, your investment would be $575. The formula is A=P(1+(r/n)^(n*t) where A is the final amount, P is the initial balance, r is the interest rate, n is the amount of time the interest is compounded in a year, and t is the amount of time that has passed.
P=500
r= 5% is which converted into a decimal by dividing 5 by 100 which is then 0.05
n= 1 since it is compounded annually
t= 3
Hope this helped.

3 0

3 years ago

Rectangle WXYZ was dilated to create W'X'Y'Z'.

Snezhnost [94]

You did not attach any picture to solve this problem. We cannot calculate for the value W’X’ without the correct illustrations. However, I think I found the correct one (see attached), please attach it next time.

So the first thing we have to do is to calculate for the dilation factor. Taking point G as the reference point, we can see that the distance of point G from rectangle W’X’Y’Z’ is 1.5 while the distance from rectangle WXYZ is (1.5 + 7.5), therefore the dilation factor to use is:

dilation factor = 1.5 / (1.5 + 7.5) = 1.5 / 9 = 1/6

Since WX has an initial measure of 3 units, therefore the measure of W’X’ is:

W’X’ = 3 units * (1/6) = 0.5 units

Answer:

<span>0.5 units</span>

4 0

3 years ago

Read 2 more answers

Which represents a function?

VLD [36.1K]

Answer:

$\boxed{ \text{Option \: D}}$

Step-by-step explanation:

All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called vertical line test.

If the vertical line intersects the graph of a relation at one point , the relation is a function .
If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.

--------------------------------------------------

Let's check all of the options :

☐ Option A :

The vertical line cuts the graph at two points. So , the graph does not represent a function.

☐ Option B

No! This is also not a function as the vertical line cuts the graph at two points.

☐ Option C

Nah! This too can't be called a function as the vertical line cuts the graph at two points.

☑ Option D

Yep! The vertical line cuts the graph at one point. Thus , the graph represents a function.

Yayy!! We found our answer. It's ' Option D '.

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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4 0

3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

<em>The point </em> $(1\frac{1}{2},1)$ <em> won't be on the graph because the corresponding value of y for </em> $x = 1\frac{1}{2}$ <em> is </em> $y = 2\frac{1}{4}$ <em></em>

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

<em>The point </em> $(4,6)$ <em> would be on the graph because the corresponding value of y for </em> $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

<em>The point </em> $(18,12)$ <em> wouldn't be on the graph because the corresponding value of y for </em> $x = 18$ <em> is </em> $y = 12$ <em></em>

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

<em>The point </em> $(0,0)$ <em> would be on the graph because the corresponding value of y for </em> $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

<em>The point </em> $(2\frac{1}{2},3\frac{3}{4})$ <em> would be on the graph because the corresponding value of y for </em> $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago