Hello,
6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.
So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop
The answer is 37%.
(ii) For this question, we basically have the same process as the previous question except for the second year.
From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop
The answer is 12%.
6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.
The initial value of the car is 27,000, and after 5 years the value is 8,000.
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.
The answer is 70%.
Hope this helps!
After three years, your investment would be $575. The formula is A=P(1+(r/n)^(n*t) where A is the final amount, P is the initial balance, r is the interest rate, n is the amount of time the interest is compounded in a year, and t is the amount of time that has passed.
P=500
r= 5% is which converted into a decimal by dividing 5 by 100 which is then 0.05
n= 1 since it is compounded annually
t= 3
Hope this helped.
You did not attach any
picture to solve this problem. We cannot calculate for the value W’X’ without
the correct illustrations. However, I think I found the correct one (see
attached), please attach it next time.
So the first thing we have to
do is to calculate for the dilation factor. Taking point G as the reference
point, we can see that the distance of point G from rectangle W’X’Y’Z’ is 1.5
while the distance from rectangle WXYZ is (1.5 + 7.5), therefore the dilation factor
to use is:
dilation factor = 1.5 / (1.5
+ 7.5) = 1.5 / 9 = 1/6
Since WX has an initial
measure of 3 units, therefore the measure of W’X’ is:
W’X’ = 3 units * (1/6) = 0.5
units
Answer:
<span>0.5 units</span>
Answer:

Step-by-step explanation:
All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called vertical line test.
- If the vertical line intersects the graph of a relation at one point , the relation is a function .
- If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.
--------------------------------------------------
Let's check all of the options :
☐ Option A :
- The vertical line cuts the graph at two points. So , the graph does not represent a function.
☐ Option B
- No! This is also not a function as the vertical line cuts the graph at two points.
☐ Option C
- Nah! This too can't be called a function as the vertical line cuts the graph at two points.
☑ Option D
- Yep! The vertical line cuts the graph at one point. Thus , the graph represents a function.
Yayy!! We found our answer. It's ' Option D '.
Hope I helped ! ツ
Have a wonderful day / night ! ♡
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Answer:
- False
- True
-- False
-- True
-- True
Step-by-step explanation:
The points are
,
,
,
and
---- missing from the question
Given

Required
Determine if each of the points would be on 
To do this, we simply substitute the value of x and of each point in
.
(a)
In this case;
and 
becomes




<em>The point </em>
<em> won't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(b) 
In this case;


becomes





<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(c) 
In this case:

becomes





<em>The point </em>
<em> wouldn't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(d) 
In this case;

becomes


<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(e)
In this case:
; 
becomes




<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 