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antiseptic1488 [7]
3 years ago
12

Mark sold x pens for $2 each. He received less than $80 from the sale. Find the greatest possible number of pens he sold

Mathematics
2 answers:
Crank3 years ago
6 0
$80-$2= $78 is the number less than $80, since the pens cost $2

78/2= 39 pens is the greatest number of pens sold

hope this helps
Andru [333]3 years ago
4 0
Answer : 39

The answer would be 39 because he received less that 80 so subtract 2 from 80 (since each pen is $2) and you would get 78. Then you would divide 78 by 2, and that would be your answer.
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Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

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Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

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Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
3 years ago
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