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3 years ago

The speed limit on a highway is 60 mph write and graph an inequality that describes the situation

Mathematics

2 answers:

Debora [2.8K]3 years ago

5 0

Answer:

s= 60mph

i think hope it helps

kirza4 [7]3 years ago

3 0

<span>speed limit < = 60
I don't really remember how to graph it though sorry

</span>

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Simplify the expression 8x-2x+12x-3

aev [14]

Answer:

18x - 3

Step-by-step explanation:

Add all the X values

8x + -2x + 12x = 18x

Put the final numbers on the side.

-3

18x-3

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2 years ago

Jawad has seven rocks.

ad-work [718]

680 grams.

So, it's telling us to calculate the weight, in grams, of the other rock.

So firstly,

6 of the rocks EACH have a weight of 720 grams.

So, 6 x 720 = 4320

Now save 4320 for later.

Next, we need to convert the 5 kilograms into grams.

So, 5 x 1000 = 5000

now do, 5000 - 4320 = 680.

Your final answer would then be = 680g

I hope this helped.

3 0

3 years ago

4/9 divided by what equals 12

NeX [460]

(4/9)/x = 12
(4/9) = 12x
Divide both sides by 12
(1/27) =x

7 0

2 years ago

Read 2 more answers

5x5x5x5x6x7x8x8x9x9x9x9x9x9x10x12x13x14x15x16x17x18x19x20<br><br> WHAT DOES THIS EQUAL

trapecia [35]

Answer:

5.441683e+23

Step-by-step explanation:

Hope it helped brainiest plz

5 0

2 years ago

Read 2 more answers

Assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles

OverLord2011 [107]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

$A=P\left(1+r\right)^t$

Then we get equation for motorcycles and cars as:

$A=5.75\left(1+0.16\right)^t$

$A=3.5\left(1+0.25\right)^t$

Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

$3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t$

$3.5\left(1.25\right)^t>5.75\left(1.16\right)^t$

$\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}$

$\left(\frac{1.25}{1.16}\right)^t>1.64285714286$

$t\cdot\ln\left(\frac{1.25}{1.16}\right)>\ln\left(1.64285714286\right)$

$t>\frac{\ln\left(1.64285714286\right)}{\ln\left(\frac{1.25}{1.16}\right)}$

$t>6.6436473051$

Hence final answer is approx 6.644 years.

7 0

2 years ago