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EleoNora [17]
3 years ago
12

Whats the answer to this question?

Mathematics
2 answers:
erastova [34]3 years ago
7 0

Answer:

  [3, -1]

Step-by-step explanation:

The computation is performed element by element, as you appear to have figured.

  2f -g = 2[4, 1] -[5, 3] = [2·4 -5, 2·1 -3] = [8-5, 2-3]

  2f -g = [3, -1]

Tpy6a [65]3 years ago
6 0

Answer:

Try -4

Sorry if it's incorrect.

Step-by-step explanation:

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It will be 80 candidate C will get 80 because every time that you add 25 it turns to a greater number
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A small square garden has an area of 25 square yards. How long is each side of the garden?
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<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! //  :::::::::::::::::::::::::::::: ♫</h3>

➷  Area = l x w

We already have the area so substitute that in:

25 = l x w

For a square, all sides have the same length

Therefore, to get the length, simply square root 25

This would give you an answer of 5 yards.

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3 years ago
The table and graph both represent the same relationship.
timofeeve [1]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
What best describes the asymptote of an exponential function of the form f(x)=b^x?
horrorfan [7]

It depends on the value of b


Exponential functions are defined for positive values of the base [ŧex] b [/tex]. Also, they're not defined if b=1, or at least let's say that this is a trivial case, since it is the constant function 1.


Case 0<b<1:

If the base sits between 0 and 1, the exponential function is constantly decreasing. The explanation is quite intuitive, assume for the sake of simpleness that b is rational. If it sits between 0 and 1, it means that it can be written as a fraction p/q, with p<q. So, if you give a large exponent to b, you obtain


\frac{p^x}{q^x},\quad p^x \ll q^x \text{ as } x \to \infty


On the other hand, if you consider negative exponents, you switch numerator and denominator and then raise to the same exponent the fraction q/p, which gets larger and larger.


So, if 0<b<1, we have


\lim_{x \to -\infty} b^x = \infty,\qquad \lim_{x \to \infty} b^x = 0


and thus 0 is a horizontal asymptote as x tends to (positive) infinity.


Case b>1:

This case is very similar, except all roles are inverted. Now you start with a fraction p/q where p>q. So, with positive, large exponents you get


\frac{p^x}{q^x},\quad p^x \gg q^x \text{ as } x \to \infty


And as before, negative exponents switch numerator and denominator, so the fraction becomes q/p and thus you have


\lim_{x \to -\infty} b^x = 0,\qquad \lim_{x \to \infty} b^x = \infty


So, again, 0 is a horizontal asymptote, but this time for x tending towards negative infinite.

6 0
3 years ago
Read 2 more answers
Samantha reports that 60% of the first year students at her university think they should be able to bring a car to campus. She a
Nostrana [21]

Answer:

D) the standard error for her sample is 15

Step-by-step explanation:

Samantha is 95% certain that between 50% and 70% of the first year students agree that they should be able to bring a car to campus.

Here

  • 95% is the confidence level.
  • The range between 50% and 70% indicates 95% confidence interval.
  • 60% is the average proportion of the first year students at her university think they should be able to bring a car to campus.
  • 10% (0.1) is the margin of error from the mean

Since standard error can be obtained by dividing margin of error by the z-statistic of the confidence level which is 1.96. The standard error for her sample \frac{0.1}{1.96} does not equal to 15.

4 0
3 years ago
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