Given:
Hyperbola
a=55,000 km and c=81,000 km
hyperbola is the origin and the transverse axis is horizontal
Required:
Equation of the path of a satellite
Solution:
Formula for hyperbola, (x-h)2/a2 – (x-k)2/b2 = 1
At origin, (h, k) = (0, 0)
(x-0)2/(55000)2 – (x-0)2/(81000)2 = 1
<span>X2/12100 – y2/26244 = 250000</span>
Answer:
x^2/5500^2-y^2/(3536000000)=1
Step-by-step explanation:
c^2=a^2+b^2 81000^2=55000^2+b^2
b^2=3536000000, b=4000sqrt(221)
for IV you do 40^2+30^2=c, or 1600+ 900=c. c= 2500 and unsquare that you get 50
{1, 2, 3, 4, 5, 7}
x in B or C is ...
B ∪ C = {1, 2, 3, 4, 5, 7}
C
60.95 or 61msquared
