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Alinara [238K]
4 years ago
12

Somebody help plz dont get it

Mathematics
1 answer:
fiasKO [112]4 years ago
6 0
The answer is B.g(x) hope it helped!!
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Will give brainiest if correct<br><br> A. 69.1<br> B. 20.9<br> C. 22.4<br> D. 67.6
Free_Kalibri [48]
Using sin law;

sin A/ a = sinB/ b

where A = C or 90 degrees; a = 21
B = ? , b = 8

solving for b;
sin(90) / 21 = sin(B) / 8 ; B = 22.39 degrees

Total angle of triangle = 180

180 - 90 - 22.39 = x
x = 67.607 degrees
8 0
3 years ago
Read 2 more answers
An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and
egoroff_w [7]

Answer:

a) P(140

P(0.036

P(0.036

b) P(140< \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(139,28.1)  

Where \mu=139 and \sigma=28.1

We are interested on this probability

P(140

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(140

And we can find this probability like this:

P(0.036

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(0.036

Part b

For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=139, \frac{\sigma}{\sqrt{n}}=\frac{28.1}{\sqrt{32}}=4.97)

And the new z score would be:

Z=\frac{\bar X -\mu}{\sigma_{\bar x}}

P(140< \bar X

P(140< \bar X

5 0
3 years ago
Equation: -5 3/4- 3 1/2 Please help meh. ​
vampirchik [111]

Answer:

-9\frac{1}{4}

Step-by-step explanation:

-5\frac{3}{4}-3\frac{1}{2}

Step 1: Factor out the common term -1

=-\left(5\frac{3}{4}+3\frac{1}{2}\right)

Step 2: Add the whole numbers

5 + 3 = 8

Step 3: Combine the fractions:

\frac{3}{4}+\frac{1}{2} = \frac{5}{4}\\\\=-\left(8+\frac{5}{4}\right)

Step 4: Convert the improper fractions to mixed numbers

\frac{5}{4} = 1\frac{1}{4}\\\\=-\left(8+1\frac{1}{4}\right)

Step 5: Add the numbers

8 + 1 =9 \\\\=-9\frac{1}{4}

Therefore, the answer to the equation is -9\frac{1}{4} in fraction, and decimal; 9.25

4 0
3 years ago
The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
2 years ago
What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ​ ) 9x (, start fraction, 6, divided by, 17, end
sineoko [7]

We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}

6 0
3 years ago
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