3 years ago

What is the solution to the given equation? X^2+3x+7=0

Mathematics

1 answer:

Gekata [30.6K]3 years ago

7 0

Answer:

-19

well i think it the answer

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Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side o

Kipish [7]

Answer:

$y=-\frac{4}{7} x+\frac{55}{7}$

Step-by-step explanation:

Change the given equation to slope-intercept to get $y=\frac{7}{4}x-\frac{1}{4}$ . When you multiply the slopes of perpendicular lines, you get -1. -1 divided by $\frac{7}{4}$ is $-\frac{4}{7}$ . The slope of the new line is then $-\frac{4}{7}$ . The perpendicular line passes through (5, 5) so you can have the equation $5=-\frac{4}{7} (5)+b$ . Simplifying gets $b = \frac{55}{7}$ . So now the final equation for the perpendicular line is $y=-\frac{4}{7} x+\frac{55}{7}$