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Crazy boy [7]
3 years ago
7

Suppose f(x) = x^2. Find the graph of f (x-5). -Graph 1 -Graph 2 -Graph 3 -Graph 4

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

Answer:

x²-10x+25

Step-by-step explanation:

f(x) = x²

<h3>i) substitute the x-5 into x</h3>

f(x-5) = (x-5)²

<h3>ii) using the formula (a-b)² = a²-2ab+b², expand the expression</h3>

f(x-5) = (x-5)²

= x²-2(5x)+5²

<h3>iii) calculate the products</h3>

f(x-5) = x²-2(5x)+5²

= x²-10x+25

* the pic i inserted shows the shape of your graph

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Part 2

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Part 4

(5^2-9\cdot3)^2-11=(25-27)^2-11 \\  \\ =(-2)^2-11=4-11=-7



Part 5

[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\  \\ =(1-5)\cdot4=-4\cdot4=-16



Part 6

12-11\cdot2+16\div8=12-22+2 \\  \\ =-8



Part 7

-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\  \\ =-2-(-1)=-2+1=-1



Part 8

8+2\cdot3-14\div7=8+6-2 \\  \\ =12



Part 9

(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\  \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\  \\ =36+4=40



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7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\  \\ =7+(-7)\cdot5=7+(-35)=7-35 \\  \\ =-28



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3-2[2^3+(-1)^3]=3-2[8+(-1)] \\  \\ =3-2(8-1)=3-2(7)=3-14 \\  \\ -11



Part 12

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Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
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Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

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By process of elimination, a must be true. You can test w/ our example ratios:
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(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
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3 years ago
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