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almond37 [142]
3 years ago
14

The area of the base of a prism is 50mm2. The perimeter of the base is 30mm. The height of the prism is 7mm.

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
2*50+30*7=100+210=310mm2

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What is 4x+3y+2z and 3x+5y+3z?
My name is Ann [436]

Answer:

Step-by-step explanation:

7x + 8y + 5z

I put the equations in parentheses, assuming that I would be adding both of the equations together. Then, I removed them and combined the like terms. I used two calculators to check my answer, and this should be correct.

6 0
3 years ago
Read 2 more answers
2(x + 2) + 2 = 2(x + 3) + 1
Maslowich

Answer:

No solution

Step-by-step explanation:

5(x + 4) – x = 4(x + 5) – 1

x = ?

Solution:

5(x+4)−x=4(x+5)−1

Apply Distributive property:

  • (5)(x)+(5)(4)−x=(4)(x)+(4)(5)−1
  • 5x+20−x=4x+20−1

Combine Like Terms:

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  • 4x+20=4x+19

Subtract 4x from both sides:

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  • 20=19

Subtract 20 from both sides:

  • 20−20=19−20
  • 0=−1

There isn't any solutions.

6 0
2 years ago
Yo!!!NEED HELP!!!!WILL GIVE BRAIN!!!!!!!
yawa3891 [41]
First, we are going to find if the function is odd or even. Remember that we can determine if a function is odd of even from its graph by looking at its ends; if both ends go to the same the direction, the function is even. If both ends go to opposite directions, the function is odd. At both ends, the graph of our function go towards the same direction, minus infinity, so we can conclude that our function is even.

Next, we are going to find the possible degree of our function. Remember that the possible degree of a function is the number of x-intercepts.
We can infer from our graph that the function intercepts the x-axis at least 6 times.

We can conclude that the correct answer is: even degrees of 6 or greater.
5 0
3 years ago
What is they intercept of 9<br>​
Ugo [173]

Answer:

i dont know i am so sorry

Step-by-step explanation:

good luck with it though

6 0
3 years ago
5. Solve using any method.<br> y = -x + 8<br> y=x+4
vlada-n [284]

Answer:

<h2>x = 2, y = 6 → (2, 6)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

7 0
3 years ago
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