F(x) = x^2 + 1
f(4) = 4^2 + 1 = 16 + 1 = 17
2*f(4) = 2 * 16 = 32
First statement: False. Points K, M and N form a triangle.
Second statement: True. Points J, K, and Q are on the same line.
Third statement: False. KN and MQ intersect at N, not at R.
Fourth statement: False. JQ and KM intersect at K, but MQ does not pass through it.
Fifth statement: True. By definition, there is always only 1 line that can be drawn between 2 given points.
Answer
go to your math teacher and ask him to explain more
Answer:
Neither
Step-by-step explanation:
We need to transform one of the equations into its slope-intercept form:
y + 2/5x = 8
Subtract 2/5x from both sides:
y = -2/5x + 8
y = -5/2x - 7
Graphing both lines, they do intersect at point (-7.14, 10.86), but they are not parallel, nor are they perpendicular from each other. By definition, perpendicular lines must appear to be perpendicular (that is, they intersect at a 90° angle).
Looking at the attached graph (where the purple line is y = -2/5x + 8), their lines do not form a 90° angle.
Therefore, the correct answer is neither.
Please mark my answers as the Brainliest, if you find my explanations helpful :)
Answer:
letss seeee
Step-by-step explanation:
c.