Evaluate p+(n-1) x3 for n=7 and p=9

1 answer:

8 0

Is x3 an exponent ? i answered one of ur earlier questions and i assumed x3 was multiplication

9 + (7 - 1)^3
= 9 + (6)^3
= 9 + (216)
= 225

or if it is multiplication...

then the answer is 27

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What is the area of the sector shown in the picture

tatuchka [14]

Answer:

The area of the sector shown is 4.75 pi

Step-by-step explanation:

First we have to know what fraction of the total circle that part represents

for that we divide 45 by 360

45/360 = 1/8

now we calculate the area of the circle and divide it by 8

a = ( π * 6² ) / 8

a = ( π * 36 ) / 8

a = π * 4.75

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7 0

3 years ago

What is the midpoint between the points (1, 4) and (-3, 2)?

emmasim [6.3K]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ -3}}\quad ,&{{ 2}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
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