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erica [24]
3 years ago
5

Evaluate p+(n-1) x3 for n=7 and p=9

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0
Is x3 an exponent ? i answered one of ur earlier questions and i assumed x3 was multiplication

9 + (7 - 1)^3
= 9 + (6)^3
= 9 + (216)
= 225

or if it is multiplication...

then the answer is 27
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A laptop is in the shape of a rectangular prism. The laptop has a length of 14 inches, a width of 10 inches, and a height of 1 i
Aleks04 [339]

Answer:

140 inches

Step-by-step explanation:

The formula for volume or a rectangular prism is v=lwh

Length = 14

Width= 10

Height= 1

Multiplying them together gives you the volume which is 140

6 0
4 years ago
The midpoint of segment ST is M(5,2). One endpoint is S(-1, -7). Find the coordinates of the other endpoint.
Tasya [4]

Answer:

The other endpoit has this cordinadetes (11, 11).

Step-by-step explanation:

Midpoint (MD) (Xm, Ym)

Xm = 5

Ym = 2

Xm of the Midpoint:    Xm = X1 + X2/ 2

Ym of the Midpoint:    Ym = Y1 + Y2/2

<em>We can say that S is (x1, y1), so x1 = -1 and y1 = -7</em>

Then:

Xm = -1 + x2/2

5= -1 + x2/2

10 = -1 + x2

x2 = 11

Also:

Ym = -7 + y2/2

2 = -7 + y2/2

4 = -7 + y2

11 = y2

8 0
3 years ago
✨Help a bestie out:
cestrela7 [59]

Answer:

Nasa taas po ang sagot

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4 0
3 years ago
2. The sum of three consecutive integers is 48. What are the three integers?
Natasha2012 [34]

Answer: 15, 16, 17

Step-by-step explanation: you have to divide 48 by 3 when you do this then you get the center number in this case 16 so all you have to do now is add the lower number (15) and the higher number (17) and add and they will equal 48

hope this helps please mark brainliest if it helps

5 0
3 years ago
A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min
Dmitry [639]

At any time t (min), the volume of solution in the tank is

500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}

If A(t) is the amount of salt in the tank at any time t, then the solution has a concentration of \dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}.

The net rate of change of the amount of salt in the solution, A'(t), is the difference between the amount flowing in and the amount getting pumped out:

A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)

Dropping the units and simplifying, we get the linear ODE

A'=10+5\sin\dfrac t4-\dfrac A{10}

10A'+A=100+50\sin\dfrac t4

Multiplying both sides by e^{10t} allows us to identify the left side as a derivative of a product:

10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}

\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}

e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt

Integrate and divide both sides by e^{10t} to get

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}

The tanks starts off with 30 lb of salt, so A(0)=30 and we can solve for C to get a particular solution of

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}

6 0
4 years ago
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