For a you check the unit rate. Every 1 second mika moves, she goes 4.2 meters. From the graph, check 1 on the x axis and then check the y. The y is 3.5, so mika is faster because her unit rate is faster.
Answer:
-15 and 1
Step-by-step explanation:
-15x1=-15
-15+1= -14
The linear inequality of the graph is: -x + 2y + 1 > 0
<h3>How to determine the
linear inequality?</h3>
First, we calculate the slope of the dashed line using:

Two points on the graph are:
(1, 0) and (3, 1)
The slope (m) is:

This gives
m = 0.5
The equation of the line is calculated as:

So, we have;

This gives

Multiply through by 2

Now, we convert the equation to an inequality.
The line on the graph is a dashed line. This means that the inequality is either > or <.
Also, the upper region of the graph that is shaded means that the inequality is >.
So, the equation becomes
2y > x - 1
Rewrite as:
-x + 2y + 1 > 0
So, the linear inequality is: -x + 2y + 1 > 0
Learn more about linear inequality at:
brainly.com/question/19491153
#SPJ1
<u>Complete question</u>
Find a linear inequality with the following solution set. Each grid line represents one unit. (Give your answer in the form ax+by+c>0 or ax+by+c
0 where a, b, and c are integers with no common factor greater than 1.)