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Furkat [3]
3 years ago
13

Combine like terms to find the equivalent expression to6(58u+1)−6(−74u−5). PLEASEEEE HELPPP I NEEEDDD HELP

Mathematics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

-36 • (22u + 1)

Pulling out like terms :

2.1     Pull out like factors :

  -74u - 5  =   -1 • (74u + 5)

Equation at the end of step  2  :

 (6 • (58u + 1)) -  -6 • (74u + 5)

Step  3  :

Equation at the end of step  3  :

 6 • (58u + 1) -  -6 • (74u + 5)

Step  4  :

Pulling out like terms :

4.1      Pull out     6

Note that  -6 =(-1)• 6

After pulling out, we are left with :

     6 • ( (-1)  *  (58u+1) +( (-1)  *  (74u+5) ))

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  -132u - 6  =   -6 • (22u + 1)

Final result :

 -36 • (22u + 1)

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Hoochie [10]
The required answer is 10.5
6 0
3 years ago
Jerold reads at a rate of 3 pages in 2 minutes. He as a 2427 page novel to read and a 906 page mystery book to read. How long wi
g100num [7]

Answer:

1618 minutes

Step-by-step explanation:

Jerold reads at a rate of 3 pages in 2 minutes. He as a 2427 page novel to read and a 906 page mystery book to read. How long will it take him to read his novel?

From the question above, the number of pages for his novel = 2427 pages

His reading rate =

3 pages = 2 minutes

Hence:

3 pages = 2 minutes

2427 pages = x minutes

Cross Multiply

3 pages × x = 2427pages × 2 minutes

x = 2427pages × 2 minutes/3 pages

x = 1618 minutes

It would take him 1618 minutes to read his 2427 paged novel

3 0
3 years ago
Population in a Small Town, USA was 5,054 in 2007. The populations increase by 2% annually. Show and explain all work.
kakasveta [241]

Answer: a. f(x)=5054(1.02)^x

b. The population in 2032 will be 8292.

Step-by-step explanation:

Exponential growth equation: y=a(1+r)^x, where a = initial value , r = growth rate, x = time period

Given: a = 5054 , r= 0.02

a. Required exponential growth function: f(x)=5054(1+0.02)^x

f(x)=5054(1.02)^x

b. For 2032, x= 25

f(25)=5054(1.02)^{25}

\approx8291.62\approx8292

The population in 2032 will be 8292.

5 0
2 years ago
∠EFG and ∠GFH are a linear​ pair, m∠EFG=3n+19, and m∠GFH=55+33 What are m∠EFG and m∠​GFH?
romanna [79]
A linear pair is a pair of angles that form a straight line and are therefore, equal to 180 degrees

3n + 19 + 55 + 33 = 180
3n + 107 = 180
3n = 180 - 107
3n = 73
n = 73/3 


so < EFG = 3n + 19 = 3(73/3) + 19 = 73 + 19 = 92
and < GFH = 55 + 33 = 88
5 0
3 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
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