This problem can be solve by using ration and proportion, since you want to enlarge the picture by not distorting the image, the new dimensions should be in proportion with the old one.

Let x be length of the image

(5/40 = (x/5)

X = 5(5/4)

3 0

4 years ago

Solve for x.

jolli1 [7]

X= -292 1/2

the picture should explain, but i can explain further

8 0

3 years ago

To put up several tents for a camping trip, you need several pieces of rope each 6 2/3 feet long. If you have a rope that is 43

Otrada [13]

$\bf 43\div 6\frac{2}{3}\implies \cfrac{46}{6\frac{2}{3}}\implies \cfrac{\frac{46}{1}}{\frac{6\cdot 3+2}{3}}\implies \cfrac{\frac{46}{1}}{\frac{20}{3}} \implies \cfrac{46}{1}\cdot \cfrac{3}{20}\implies \cfrac{69}{10}
\\\\\\
\boxed{6\frac{9}{10}}\qquad \qquad 
\cfrac{6\cdot 10+9}{10}\implies \cfrac{69}{10}$

3 0

3 years ago