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Arturiano [62]
3 years ago
12

A 4 in. by 5 in. photo is enlarged so that its width (shorter dimension) is 5 in. What is the length of the enlarged photo? 5.25

in. 6 in. 6.25 in. 7 in.
Mathematics
1 answer:
Papessa [141]3 years ago
3 0

This problem can be solve by using ration and proportion, since you want to enlarge the picture by not distorting the image, the new dimensions should be in proportion with the old one.

Let x be length of the image

(5/40 = (x/5)

X = 5(5/4)

<span>X = 6.25 in</span>

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Help please! Find the perimeter of the rectangle.
Umnica [9.8K]

Answer:

34

Step-by-step explanation:

We know the area is 52 cm and that one length is 13cm. This means that in order to find the missing length, we need to divide 52 by 13. this gives us 4, meaning that the missing side is 4 cm.

Now we add 26 (Double of 13 because it is both sides) to 8 (Double of 4 because they are same lengthening sides)

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Hope this helps :)

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5 0
3 years ago
Read 2 more answers
I can't find the surface area because I have no clue where to find the radius
Vladimir79 [104]
You are told the circumference of the sphere. The circumference is the length of the circle around the widest part. You know the formula for the circumference of a circle in terms of radius, so you can find the radius of the sphere.

C = 2πr
496.12 yd = 2*3.14*r
(496.12 yd)/(2*3.14) = r = 79 yd

Then the surface area of a sphere is given by ...
A = 4πr^2
A = 4*3.14*(79 yd)²
A = 78,386.96 yd²


_____
You can also find the area of a sphere in terms of its circumference.
A = C²/π
A = (496.12 yd)²/3.14 = 78,386.96 yd² . . . . same as above.

(The surface area in your problem statement, 3117.25 yd², corresponds to a sphere with a circumference of about 98.94 yd. The circumference given in the problem statement is almost 5 times that, which is why the area is almost 5²=25 times the area in your problem statement. This is a good one to ask your teacher about.)
3 0
4 years ago
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Jobisdone [24]

Answer:

2

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The track and field team ran 2 2/3 laps around the track

Therefore the number of miles ran by the team can be calculated as follows

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= 8/3 × 3/4

= 2

Hence the team ran 2 miles

5 0
3 years ago
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