we know that
the rate of a linear equation is equal to the slope
Step 1
Find the bear’s average heart rate when it’s active
Let
A(1.5,90) B ( 2,120)
the slope is equal to
m=(y2-y1)/(x2-x1)
m=(120-90)/(2-1.5)=30/0.5
m=60 heartbeats/min
therefore
the answer part a) is
the bear’s average heart rate when it’s active is 60 heartbeats/min
Step 2
Find the bear’s average heart rate when it’s hibernating
Let
A(1.5,18) B ( 2,24)
the slope is equal to
m=(y2-y1)/(x2-x1)
m=(24-18)/(2-1.5)=6/0.5
m=12 heartbeats/min
therefore
the answer part b) is
the bear’s average heart rate when it’s hibernating is 12 heartbeats/min
The clock breaks down to a different number sequence 2 B .5 it would be half past the hour 15 minutes past the hour would be 1 / 4 or .25
Answer:
Is there a photo for this I don't have much info.
Step-by-step explanation:
3x-5y=20 the answer is y= 4x+-1/3
the length of the fish tank is
. Correct option is A)
<u>Step-by-step explanation:</u>
Here we have , Peter has just purchased a small rectangular fish tank that holds 910 milliliters of water. The tank has a width of 7 cm and a height of 10 cm. We need to find What is the length of the fish tank . Let's find out:
The fish tank is in the shape of cuboid , and we know that volume of cuboid :
⇒ 
Now , according to question we have following parameters :

Therefore , Putting theses values in above equation we get :
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the length of the fish tank is
. Correct option is A)