Question

A ball whirls around in a vertical circle at the end of a string. The other end of the string is fixed at the center of the circle. Assume that the total energy of the ball-Earth system remains constant. (a) What is the tension in the string at the bottom?

Answer 1

Answer:

Explanation:

Given

Let T be the tension in the string at the Bottom Point

thus

$T-mg=\frac{mv^2}{r}$

$T=mg+\frac{mv^2}{r}$

where m=mass of string

r=radius of circle

v=velocity at bottom point

and T_0 be the tension at highest Point

$T_0+mg=\frac{mv^2}{r}$

$T_0=\frac{mv^2}{r}-mg$