A ball is thrown against a wall and bounces back toward the thrower with the same speed as it had before hitting the wall. Does
1 answer:
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The mirror is located 30 cm from the object
Explanation:
To solve the problem, we can use the magnification equation, which states that:
where
M is the magnification
y' is the size of the image
y is the size of the object
q is the distance of the image from the mirror
p is the distance of the object from the mirror
In this problem, we notice that the image formed by the mirror is erect and diminished: this means that this is a convex mirror, so the image is virtual, and this means that the image and the object are located on opposite sides of the mirror. Therefore,
(distance of the image from the object is 40 cm, but since the image is virtual, q is the negative)
The size of the image is 1/3 that of the object, so
Solving the equation for p, we find the distance between the object and the mirror:
So, the mirror is 30 cm from the object.
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