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mihalych1998 [28]
3 years ago
10

A ball is thrown against a wall and bounces back toward the thrower with the same speed as it had before hitting the wall. Does

the velocity of the ball change in this process?A) Although the speed is the same, the direction has changed. Therefore, the velocity has changed.B) The velocity is the same because the speed is the same.C) Without knowing the mass of the ball, the velocity is not determined.D) The velocity is now twice as large because the ball is going into the opposite direction.
Physics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

A) Although the speed is the same, the direction has changed. Therefore, the velocity has changed.

Explanation:

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If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical
erastovalidia [21]

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

<h3>Time of motion of the girl</h3>

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

  • v is initial vertical velocity = 0
  • t is time of motion
  • g is acceleration due to gravity

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

<h3>Final vertical velocity of the skydiver</h3>

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

Learn more about vertical velocity here: brainly.com/question/24949996

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2 years ago
All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will
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5.5 s

Explanation:

The time it takes for the ball to reach its maximum height can be calculated using

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since v_y = 0 at the top of its trajectory. Plugging in the numbers,

t = \dfrac{(54\:\text{m/s})}{(9.8\:\text{m/s}^2)} = 5.5\:\text{s}

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