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4 years ago

USE FOR ALL PROBLEMS: You are comparing two cell phone plans. Xfinity offers

Mathematics

2 answers:

Fittoniya [83]4 years ago

4 0

^^^^^^^^^^^^^^^^^^^^^^^^^^^^

mr Goodwill [35]4 years ago

3 0

It would be xfinity because your spending only $45 but on t mobile your spending $75

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Please give real answers with an explaination. 30 points + I will give brainliest. No Docs/No Files/No Links only answer with ex

Anon25 [30]

Answer:

option A

Step-by-step explanation:

The line splits the triangle ABC into two triangles with same base length.

Therefore ,

$Area \ of \ ABC = Area \ of \ ABD + Area \ of \ CBD\\\\$

$= (\frac{1}{2} \times base \times height) + (\frac{1}{2} \times base \times height)\\\\=(\frac{1}{2} \times AD \times BD) + (\frac{1}{2} \times CD \times BD)\\\\=(\frac{1}{2} \times AD \times BD) + (\frac{1}{2} \times AD \times BD)$ $[ \ Given : AD = \ CD \ ]$

$= 2 \times (\frac{1}{2} \times AD \times BD)\\\\= 2 \times Area \ of \ ABD$

5 0

3 years ago

The total price of a bag of peaches varies directly with the cost per pound. If 3 pounds of peaches cost $3.60, how much would 5

Levart [38]

<h3>Therefore the cost of 5.5 pound of peaches is $ 6.60.</h3>

Step-by-step explanation:

Given , the total price of a bag of peaches varies directly with the cost per pound. If 3 pound of peaches cost $3.60.

Therefore,

${\textrm{beg of peaches}}\propto{\textrm{cost}}$

$\Leftrightarrow {\textrm{beg of peaches}}= {\textrm{k cost}}$ .......(1) [ k is a constant]

cost = $3.60 when beg of peaches = 3 pounds

$3 = 3.60 k$

$\Leftrightarrow k = \frac{3}{3.60}$

$\Leftrightarrow k = \frac{1}{1.20}$

Therefore the equation (1) becomes

${\textrm{beg of peaches}}=\frac {cost}{1.20}$

$\Leftrightarrow {\textrm{beg of peaches}}\times 1.20={cost}$

When beg of peaches = 5.5 pound

$cost = 5.5 \times 1.20$

$\Leftrightarrow cost = 6.60$

Therefore the cost of 5.5 pound of peaches is $ 6.60.

8 0

3 years ago

Simplify 5/9x4 3/5x6 3/11x6/10 and 3 4/5x7 1/2

Sav [38]

Answer:

529/55 and 57/2

Step-by-step explanation:

4 0

2 years ago

If the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20

zysi [14]

Answer:

Therefore, we conclute that the map distance between A and C is 35 m.u..

Step-by-step explanation:

We know that the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20 m.u. We calculate the map distance between A and C.

Therefore, we get

$AC=AB+BC\\\\AC=15+20\\\\AC=35\\$

Therefore, we conclute that the map distance between A and C is 35 m.u..

4 0

3 years ago

Write an equivalent expression for 1/y-1/4

kenny6666 [7]

We have the expression $\frac{1}{y- \frac{1}{4} }$ . To write a equivalent expression, we are going to rewrite the denominator of our expression using its common denominator 4:
$\frac{1}{y- \frac{1}{4} } = \frac{1}{ \frac{4y-1}{4} }$
Now, notice that we are basically diving 1 by $\frac{4y-1}{4}$ , so we have a division involving fractions, and remember that to divide fractions, we just need to invert the second fraction and multiply:
$\frac{1}{ \frac{4y-1}{4} } =1* \frac{4}{4y-1} = \frac{4}{4y-1}$

We can conclude that the equivalent expression of $\frac{1}{y- \frac{1}{4} }$ is $\frac{4}{4y-1}$ .

7 0

4 years ago