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3 years ago

A quarterback completed 16% of his passes in a season. He completed 80 passes. How many passes did the quarterback throw?

Mathematics

1 answer:

drek231 [11]3 years ago

5 0

Answer:

500

Step-by-step explanation:

100*80 is 8000, then divide it by 16

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For every for female students in a training class there are two men what is the ratio of female to male students

Katyanochek1 [597]

For every for female students in a training class there are two men what is the ratio of female to male students.

Answer:

1:2

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4 years ago

Which measurement statement is correct? There are 2 cups in a pint. There are 2 pints in a cup. There are 4 quarts in a pint. Th

anzhelika [568]

There are 2 cups in a pint

3 0

3 years ago

Read 2 more answers

X/4+10=16 really need it asap

Luba_88 [7]

Answer:

x = 24

Step-by-step explanation:

x/4 + 10 = 16

x/4 = 16 - 10

x/4 = 6

x = 6 · 4

x = 24

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3 years ago

Read 2 more answers

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$

c) P(completing the exam in more than 90 minutes)

P(x > 90)

$P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

$\dfrac{15.87}{100}\times 60 = 9.52\approx 10$

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0

4 years ago

What is 13 = t/9 - 1 I NEED HELPP!!!!!!!!!!!!!!!!!!!

Gekata [30.6K]

T = 126.

13 = t/9 - 1 multiply both sides by 9
117 = t - 9 move terms
-t = -9 - 117
-t = -126 change the signs
t = 126

3 0

3 years ago