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3 years ago

5

You buy some post cards at 55cents each and one newspaper for 35cents. Which could be used to determine the number of post cards

(p) you can buy if you only have $2

1 answer:

Radda [10]3 years ago

8 0

3 post cards and 1 newspaper can be bought

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The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 14

Salsk061 [2.6K]

<u>Question Completion</u>

PIE CHART NUMBERS:

Excellent 9%
Good 41%
Fair 36%
Poor 13%
Other 1%

Answer:

0.000063

Step-by-step explanation:

Number of Respondents, n=1400

Probability that they would rate their financial shape as excellent = 0.09

Number of Those who would rate their financial shape as excellent

=0.09 X 1400

=126

Therefore:

The probability that 4 people chosen at random would rate their financial shape as excellent

$=\dfrac{^{126}C_4 \times ^{1400-126}C_0}{^{1400}C_4} \\=\dfrac{^{126}C_4 \times ^{1274}C_0}{^{1400}C_4}\\=0.000063 $(correct to 6 decimal places)$

6 0

3 years ago

PLEASE HELP ME LINK IS BELOW

n200080 [17]

Answer:

55

Step-by-step explanation:

Since there is a right angle at the bottom, we know that x and angle 35 degrees form a right angle so 90 minus 35 is 55.

8 0

3 years ago

Read 2 more answers

Help me please this is for a math test. <br> Thank you

zubka84 [21]

Answer:

x + 3y = -12

Step-by-step explanation:

y = mx + b

m is the slope = rise / run:

rise = 1

run = 3

the line is downhill so its negative

m = - 1 / 3

b is the y intercept which is when the line cross over the y axis: - 4

y = - 1/3x - 4

multiply both sides by 3

3y = -1x - 12

add x to both sides

x + 3y = -12

7 0

2 years ago

(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13

jolli1 [7]

Answer:

$y(x)=3e^{5x}-2xe^{5x}$

Step-by-step explanation:

The given differential equation is $y''-10y'+25y=0$

The characteristics equation is given by

$r^2-10r+25=0$

Finding the values of r

$r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5$

We got a repeated roots. Hence, the solution of the differential equation is given by

$y(x)=c_1e^{5x}+c_2xe^{5x}...(i)$

On differentiating, we get

$y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)$

Apply the initial condition y (0)= 3 in equation (i)

$3=c_1e^{0}+0\\\\c_1=3$

Now, apply the initial condition y' (0)= 13 in equation (ii)

$13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2$

Therefore, the solution of the differential equation is

$y(x)=3e^{5x}-2xe^{5x}$

5 0

3 years ago

A chemist has a 40% alcohol solution and a 25% alcohol solution. How much of each should he mix together to get 50 liters of a 3

ludmilkaskok [199]

Answer:

33 1/3 L of the 40% solution, 16 2/3 L of the 25% solution

Step-by-step explanation:

Set up two equations...

Let x represent the number of Liters of the 40% solution

Let y represent the number of Liters of the 25% solution

We need 50 liters total, so

x + y = 50

and we need the 50 L to be 35% solution, so

0.4x = 0.25y = 0.35(50)

Solve the first equation for one variable...

x = 50 - y (subtract y from both sides in equation 1)

Now substitute that value into the second equation...

0.4(50 - y) + 0.25y = 17.5 (x becomes 50 - y, 0.35(50) = 17.5)

Now solve for y...

20 - 0.4y + 0.25y = 17.5

-0.15y = -2.5

y = 16.66666667

y = 16 2/3 L

So we need to plug that into the first equation to find 'x'

x + 16 2/3 = 50

x = 50 - 16 2/3

x = 33 1/3

3 0

3 years ago

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