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Daniel [21]
4 years ago
15

What is the Slope and y intercept

Mathematics
1 answer:
Inessa [10]4 years ago
5 0

Answer:

The slope is .075 and the y intercept is -.125

Step-by-step explanation:

8y = .2(3x -5)

Distribute the .2

8y = .6x - 1

Divide by 8

8y/8 = .6x/8 -1/8

y = .075x -.125

This is in slope intercept form  y= mx+b  where m is the slope and b is the y intercept.

The slope is .075 and the y intercept is -.125

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He would need $210 per month, so round to $200
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3 years ago
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One-quarter of the counters in a tub are red. The rest of the counters are green. If there are 48 green counters, how many red c
scZoUnD [109]

There are 16 red counters there.

<h3>Fractions and proportions</h3>

If one-quarter of the counters in a tub are red and the rest are green, then there are three-quarter of the counter in the tub.

Let the total counter be x such that

3/4x = 48

3x = 4 * 48

x = 4 * 16

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Determine the amount of red counter

Red counter = 64 - 48

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Hence there are 16 red counters there.

Learn more on proportion here; brainly.com/question/1496357

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6 0
2 years ago
Tyler's mom purchased a savings bond for Tyler. The value of the savings bond increases by 4% each year. One year after it was p
Gemiola [76]

Answer:

The value of the bond when Tyler's mom purchased it was $150

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

f(x)=a(b)^{x}

where

a is the initial value (y-intercept)

b is the base

r is the rate

b=(1+r)

In this problem

r=4%=4/100=0.04

b=1+0.04=1.04

substitute

f(x)=a(1.04)^{x}

where

x is the number of years since the savings bond was purchased

f(x) is the value of the savings bond

For x=1

f(x)=$156

substitute

156=a(1.04)^{1}

Solve for a

156=a(1.04)

a=\$150

therefore

The value of the bond when Tyler's mom purchased it was $150

8 0
4 years ago
In ∆ABC the angle bisectors drawn from vertices A and B intersect at point D. Find ∠ADB if: m∠С = γ
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Answer:

  90° + (γ/2)

Step-by-step explanation:

The angles in ΔADB have a sum of 180°, so ...

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and so do the angles of ΔABC:

  A + B + γ = 180°

Dividing this second equation by 2 gives an expression for (A/2) +(B/2) that we can substitute into the first equation:

  A/2 +B/2 +γ/2 = 90°

  A/2 +B/2 = 90° -γ/2

Putting this in the first equation, we have ...

  (90° -γ/2) + ∠ADB = 180°

  ∠ADB = 90° +γ/2 . . . . . . . . . .  add (γ/2 -90°)

3 0
4 years ago
Nonpermissable replacement for a in 4/-9a
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If a=0, then the denominator is equal to 0.  Since you cannot divide by zero, you are not allowed to do this.
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