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Daniel [21]
3 years ago
15

What is the Slope and y intercept

Mathematics
1 answer:
Inessa [10]3 years ago
5 0

Answer:

The slope is .075 and the y intercept is -.125

Step-by-step explanation:

8y = .2(3x -5)

Distribute the .2

8y = .6x - 1

Divide by 8

8y/8 = .6x/8 -1/8

y = .075x -.125

This is in slope intercept form  y= mx+b  where m is the slope and b is the y intercept.

The slope is .075 and the y intercept is -.125

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Root of 0.792 = 0.89
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2 years ago
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What is the length of a diagonal of a cube with a side length of 10 cm? 200 cm 210cm 300 cm 320cm
Scilla [17]

Answer:

The length of the diagonal of the cube = √(3 × 10²) = √300 cm

Step-by-step explanation:

* Lets revise the properties of the cube

- It has six equal faces all of them are squares

- It has 12 vertices

- The diagonal of the cube is the line joining two vertices in opposite

 faces (look to the attached figure)

- To find the length of the diagonal do that:

# Find the diagonal of the base using Pythagoras theorem

∵ The length of the side of the cube is L

∵ The base is a square

∴ The length of the diagonal d = √(L² + L²) = √(2L²)

- Now use the diagonal of the base and a side of a side face to find the

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∵ d = √(2L²)

∵ The length of the side of the square = L

∴ The length of the diagonal of the cube = √[d² + L²]

∵ d² = [√(2L²)]² = 2L² ⇒ power 2 canceled the square root

∴ The length of the diagonal of the cube = √[2L² + L²] = √(3L²)

* Now lets solve the problem

∵ The length of the side of the square = 10 cm

∴ The length of the diagonal of the cube = √(3 × 10²) = √300 cm

- Note: you can find the length of the diagonal of any cube using

 this rule Diagonal = √(3L²)

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3 years ago
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Use Cramer's rule to find the solution to the following system of linear equations.
slavikrds [6]

Answer:

x = 53

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Step-by-step explanation:

Step(I):-

Given equations are

x -2y =-7 ...(I)

5x-9y =-5 ..(ii)

The matrix form  AX = B

                    \left[\begin{array}{ccc}1&-2\\ 5  & -9\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}-7\\-5\\\end{array}\right]

The determinant

= \left|\begin{array}{ccc}1&-2\\5&-9\\\end{array}\right| = -9+10 =1

By using Cramer's Rule

Δ₁ =      \left[\begin{array}{ccc}-7&-2\\\\-5&-9\end{array}\right]



The determinant is     Δ₁ = -9 X -7 - (10 ) = 53

x = Δ₁ / Δ

x = 53

The determinant

Δ₂ =



Δ₂ = -5 +35

     

 

y = Δ₂/Δ =  30

     

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Use the data to find the lower quartile value.
grandymaker [24]

Answer:$9.75

Step-by-step explanation:

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4 years ago
Rewarding BRAINLY FOR CORRECT ANSWER
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My answer Is The 4th Statement because a positive number is on the other side of the number line as the negative number and if it were just negative 5 and positive 5 it would be correct. I’m just trying the best I can to help you .

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