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Nutka1998 [239]
3 years ago
11

Simplify: –3(y + 2)^2 – 5 + 6y

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0
The answer is -3y^2-6y-17
jarptica [38.1K]3 years ago
5 0
I got the same answer as that person^^
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Deffense [45]

Answer:

Step-by-step explanation:

8 0
3 years ago
Tell whether (5. 10) is a solution of y = 6x – 18
almond37 [142]

Answer:

NO

Step-by-step explanation:

Simply enter 5, 10 in the x and y boxes to get the answer.

10=6(5)-18

10=30-18

10=12

As a consequence, it isn't a feasible option.

8 0
2 years ago
For each value of x, determine whether it is a solution to x&gt; 8.<br> Is it a solution?
Anni [7]

Answer:

what are the values of X?

3 0
2 years ago
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
Given the regular price of an item and the discount rate, how do you find the discount?
Allisa [31]

Answer:

discount divided by the normal/actual

Step-by-step explanation:

5 0
3 years ago
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