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3 years ago

Who is correct? Fred or Felicity?

Mathematics

2 answers:

Anon25 [30]3 years ago

8 0

Answer: Felicity

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I hope this helps, and enjoy the rest of your day!

Feliz [49]3 years ago

8 0

Felicity is correct!!!!!

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You eat 3/10 of a pack of hot dogs. Your friend eats 1/5 of the pack of hot dogs. What fraction of the pack of hot dogs do you a

GalinKa [24]

Answer:

1/2

Step-by-step explanation:

Both fractions can be expressed using a denominator of 10. The sum can be reduced by removing a common factor of 5 from numerator and denominator.

$\dfrac{3}{10}+\dfrac{1}{5}=\dfrac{3}{10}+\dfrac{2}{10}\\\\=\dfrac{3+2}{10}=\dfrac{5\cdot 1}{5\cdot 2}=\dfrac{1}{2}$

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3 years ago

What is the sign of the point pf the product of nineteen negatice numbers?

Masteriza [31]

A. Negative ♡

Im pretty sure about this

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3 years ago

The total sales of a company (in millions of dollars) t months from now are given by S(t) = 0.03t3 + 0.5t2 + 9t + 4. Find S'(t).

o-na [289]

Answer:

S'(t) = 0.09t^2 + t + 9

S(2) = 24.24

S'(2) = 11.36

S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.

S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month

Step-by-step explanation:

The derivate of the sales function S'(t) , which is the rate at which sales vary with time in months, is:

$\frac{dS(t)}{dt} =S'(t) = 0.09t^2 + t + 9$

S(2) is found by applying t=2 to S(t):

$S(2) = 0.03*(2^3) + 0.5*(2^2) + 9*2 + 4\\S(2)= 24.24$

S'(2) is found by applying t=2 to S'(t):

$S'(2) = 0.09*(2^2) + 2 + 9\\S'(2) = 11.36$

Since the sales function gives the amount of sales in millions of dollars,

S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.

S'(t) represents the rate of change in sales in millions of dollars per month.

S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month

8 0

3 years ago

Can you please answer the question?

Roman55 [17]

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that one side of the equality is equal to the expression of the other side, requiring the use of algebraic and trigonometric properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}$

$\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}$

$\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}$

$\tan \alpha + 1 + \cot \alpha$

$\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1$

$\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1$

$\frac{1}{\cos \alpha \cdot \sin \alpha} + 1$

$\sec \alpha \cdot \csc \alpha + 1$

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0

2 years ago

A wire of length 240 inches is cut into 2 equals pieces. Each piece of wire is then bent into forming an equilateral triangle an

Tamiku [17]

240 inches cut into 2 equal pieces is just taking half of the wire.
Making the two pieces of wire 120 inches.
If you bend one 120 inch wire into a square, that means that each side equals 30 inches. (A square has 4 sides. 120/4 = 30)
An area of a square is length times width, which the length equals 30 and width equal to thirty. 30 * 30 = 900. square inches.
120 wire bent into a triangle makes each side equal to 40. 120/3=40. The area of an equilateral triangle is height times width. The width is just one of the sides (40 inches) but the height needs some geometry. To find the height you need to use either 30 times sin(60) or 30 times cos(30), both are equal. To be clear, I will leave the height as 30sin(60). The area will be equal to $40*30sin(60)$
which can be simply written as 1200sin(60).
So the sum of both areas is $(1200sin(60)+900)$

7 0

3 years ago