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3 years ago

13

hello! I’m very confused on this question, I want to know if my format is good? I currently have x^2-14x=16 Am I on the right tr

ack?

1 answer:

yulyashka [42]3 years ago

3 0

Answer:

according to me

Step-by-step explanation:

yes u r correct

;]

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A survey of magazine subscribers shows that 19% rented a car during the past twelve months for business reasons, 52% rented a ca

irinina [24]

Answer:

a. 0.68 or 68%

b. 0.32 or 32%

Step-by-step explanation:

a. The probability that a subscriber rented a car during the past 12 months for business or personal reasons (P(R)) is given by the probability that they rented a car for business reasons (P(B)=0.19), added to the probability that they rented for personal reasons (P(P)=0.52), subtracted by the probability that they rented for both reasons (P(B and P) = 0.03):

$P(R)=P(B)+P(P)-P(B\cap P)\\P(R) = 0.19+0.52-0.03\\P(R)=0.68$

b. The probability that a subscriber did not rent a car during the past 12 months for either business or personal reasons (P(N)) is 100% minus the probability that they rented a car (P(R) = 0.68).

$P(N) = 1-P(R) = 1-0.68\\P(N) =0.32$

4 0

4 years ago

According to a recent Census Bureau report, 12.7% of Americans live below the poverty level. Suppose you plan to sample at rando

larisa [96]

Answer:

a) $P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928$

b) $P(X \leq 10) = 0.2614$

c) $(1-0.127)^7 (0.127) =0.0491$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=100, p=0.127)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

a. What is the probability that you count exactly 10 in poverty?

For this case we want this probability P(X=10)

$P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928$

b. What is the probability that you count 10 or less in poverty? .2614

For this case we want this probability $P(X=\leq10)$

$P(X\leq10)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)$

And we can find the individual probabilities like this:

$P(X=0)=(100C0)(0.127)^{0} (1-0.127)^{100-0}=1.263x10^{-6}$

$P(X=1)=(100C1)(0.127)^{1} (1-0.127)^{100-1}=1.837x10^{-5}$

$P(X=2)=(100C2)(0.127)^{2} (1-0.127)^{100-2}=0.000132$

$P(X=3)=(100C3)(0.127)^{3} (1-0.127)^{100-3}=0.000629$

$P(X=4)=(100C4)(0.127)^{4} (1-0.127)^{100-4}=0.00222$

$P(X=5)=(100C5)(0.127)^{5} (1-0.127)^{100-5}=0.00620$

$P(X=6)=(100C6)(0.127)^{6} (1-0.127)^{100-6}=0.0143$

$P(X=7)=(100C7)(0.127)^{7} (1-0.127)^{100-7}=0.0279$

$P(X=8)=(100C8)(0.127)^{8} (1-0.127)^{100-8}=0.0471$

$P(X=9)=(100C9)(0.127)^{9} (1-0.127)^{100-9}=0.0701$

$P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928$

And then repplacing we got:

$P(X \leq 10) = 0.2614$

c. What is the probability that you start taking the random sample and you find the first person in poverty on the 8th person selected? .0491

For this case we need after 7 people , 1 in poverty so we can find this probability like this:

$(1-0.127)^7 (0.127) =0.0491$

7 0

3 years ago

Suppose that P(n) is a propositional function. Determine for which improper subset of the domain of n the statement P(n) must be

Alinara [238K]

Answer:

a) P(n) is true for all 'n' in the set ; { 0,2,4,6,8 ….. }

b) P(n) is true for all 'n' in the set ; { 0,1,2,3,4,5 ............ }

Step-by-step explanation:

a) As P(0) is true

we will assume that

P(2) is true
P(4) is true
P(6) is true

this simply means that ; P(n) is true for all 'n' in the set

{ 0,2,4,6,8 ….. }

b) since P(0) and P(1) are true

we will assume that

P( 0+2 ) = P(2) is true

also P(1) and P(2) are true

we will assume that

P(1+2) = P(3) is true

Also from the previous answers it can be seen that P(2) + P(3) is true

we will assume

P(2+2) = P(4) is true

This simply means that P(n) is true for all 'n' in the set

{ 0,1,2,3,4,5 ............ }

8 0

3 years ago

Please help me !!...A diagram of deodorant container is shown.what is Volume

netineya [11]

Answer:

what

Step-by-step explanation:

3 0

3 years ago

How to get 2 essays and pre-essay questions done in 238 minutes? (3 hours and 58 min) PLEASE HELP

Amanda [17]

Answer:

Definitely start with outlining one essay, then doing all of your steps, although don't do much re-writing since there may not be enough time. only focus on one at a time though. as for the questions, since it says pre-essay it wants that completed first but unless you have to do it first, i would do it last since the essays are more important.

8 0

3 years ago

Read 2 more answers